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# PS: Remainders - OG 12

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Senior Manager
Joined: 30 Nov 2008
Posts: 482
Schools: Fuqua
PS: Remainders - OG 12 [#permalink]

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30 Mar 2009, 20:28
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Question Stats:

0% (00:00) correct 100% (01:02) wrong based on 1 sessions

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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

When a positive interger x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?

a) 96
b) 75
c) 48
d) 25
e) 12
Intern
Joined: 21 Sep 2008
Posts: 16
Re: PS: Remainders - OG 12 [#permalink]

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30 Mar 2009, 21:51
Option B

As x/y = 96.12

0.12Y = 9 (reminder)
--> Y = 9*100/12
--> Y = 75
Director
Joined: 25 Oct 2006
Posts: 610
Re: PS: Remainders - OG 12 [#permalink]

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30 Mar 2009, 23:15
jahnaviyeruva wrote:
Option B

As x/y = 96.12

0.12Y = 9 (reminder)
--> Y = 9*100/12
--> Y = 75

I followed the same way...
x = ay + 9 ...I
x/y = 96 + 0.12....II
=> x = 96y + 0.12y = ay + 9 ..... [from I]
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Senior Manager
Joined: 30 Nov 2008
Posts: 482
Schools: Fuqua
Re: PS: Remainders - OG 12 [#permalink]

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31 Mar 2009, 16:42
OA is B.

While I attempted this question, I forgot the concept rule that

Remainder / divisor = decimal portion.

And took me couple of min to figure randomly.
Director
Joined: 23 May 2008
Posts: 762
Re: PS: Remainders - OG 12 [#permalink]

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04 May 2009, 23:47
took me ofrever to realize that .12 =9/x ....x=75

B
Re: PS: Remainders - OG 12   [#permalink] 04 May 2009, 23:47
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