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universehk
For a quadratic function f(x)=ax^2 + bx + c, we may be aware that, in reality, f(x) can always be greater than zero. In such case, there will be no solution for x.

So far I have not encountered such cases when I am having my revision in GMAT Quantitative session. BUT, will such cases happen in GMAT?

Thanks a lot1

Understand what is meant by f(x) = ax^2 + bx + c
If we want to depict this equation on the coordinate axis, we say

y = ax^2 + bx + c is an upward sloping parabola if a is positive.

What is the meaning of solving ax^2 + bx + c = 0 for x? It means, when y = 0, what is the value of x? So you are looking for x intercepts.

What is the meaning of solving ax^2 + bx + c = d for x? It means, when y = d, what is the value of x? Depending on the values of a, b, c and d, you may or may not get values for x.

e.g. x^2 - 2x - 3 = 0
(x + 1)(x - 3) = 0
x = -1 or 3

This is what it looks like:
Attachment:
images.jpeg
images.jpeg [ 6.03 KiB | Viewed 3352 times ]

So what do you do when you have x^2 - 2x -3 = -3?
You solve it in the same way:
x^2 - 2x -3 + 3 = 0
x(x - 2) = 0
x = 0 or 2

So when y is -3, x is 0 or 2.

Similarly, you can solve for it when y = 5 and get two values for x.

What happens when you put y = -5?
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Yes, the GMAT does test the concept of a parabola not having any x-intercepts or intersecting the x-axis. Typically the question may come in a data sufficiency format and ask does the parabola y=ax^2+bx+c intersect the x-axis? Most of these problems would fall in the hardest category. Such questions have been tested in the last five years and you will not see them in the Official GMAT guides.

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