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09 Sep 2025, 07:57
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (00:57) correct
50% (00:58) wrong based on 4 sessions
History
Date
Time
Result
Not Attempted Yet
Quantity A
a
Quantity B
b
Attachment:
GMAT-Club-Forum-nq2wjxmv.png [ 13.37 KiB | Viewed 308 times ]
27 Sep 2025, 11:03
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Official Explanation
When a line passes through the origin, (0, 0), the x- and y-coordinates of any point on the line will vary directly with each other. In other words, there is some constant, k, for which \(y = kx,\) so the x-coordinate of any point on the line (in Quadrant I) will be greater than the y-coordinate, and a > b, making (A) is greater. As the slope is less than 1. Think of this as meaning that the “rise” is less than the “run,” so that the “up amount” of any point on the line, or its y-coordinate, is less than the “across amount,” or its x-coordinate. This makes \(b < a,\) and \(a > b.\)
Answer: A
When a line passes through the origin, (0, 0), the x- and y-coordinates of any point on the line will vary directly with each other. In other words, there is some constant, k, for which \(y = kx,\) so the x-coordinate of any point on the line (in Quadrant I) will be greater than the y-coordinate, and a > b, making (A) is greater. As the slope is less than 1. Think of this as meaning that the “rise” is less than the “run,” so that the “up amount” of any point on the line, or its y-coordinate, is less than the “across amount,” or its x-coordinate. This makes \(b < a,\) and \(a > b.\)
Answer: A
