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16 Sep 2011, 04:38
Kudos
Bookmarks
Hi, pls help me solve the below problem 
: :help2
A train travels from station A to station B. If it travels at a speed of 100 miles per hour, it ends up reaching the station 30 minutes late. If it travels at 120 miles per hour, it reaches the station 15 minutes early. What is the amount of time that the train is scheduled to take for the journey and what is the distance between the stations?
( ) 2 hours, 225 miles
( ) 3 hours, 350 miles
( ) 4 hours, 450 miles
( ) 5 hours, 550 miles
( ) 6 hours, 650 miles
: :help2 A train travels from station A to station B. If it travels at a speed of 100 miles per hour, it ends up reaching the station 30 minutes late. If it travels at 120 miles per hour, it reaches the station 15 minutes early. What is the amount of time that the train is scheduled to take for the journey and what is the distance between the stations?
( ) 2 hours, 225 miles
( ) 3 hours, 350 miles
( ) 4 hours, 450 miles
( ) 5 hours, 550 miles
( ) 6 hours, 650 miles
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16 Sep 2011, 05:16
Kudos
Bookmarks
Let the time taken by the train to reach the station B from station A be 'T'
The distance travelled both the times is same,
So as per the data we have,
Distance = speed *time, so
So, if the train travels at 100 m/h then it reaches, 30 min late i.e
D = 100 *(T+0.5) 30 min = 0.5hr
if the train travels at 120 m/h then it reaches, 15 min early i.e
D = 120 *(T-0.25) 15 min = 0.25hr
so, solving both the equations, we have
100*(T+0.5) = 120*(T-0.25)
T= 4hrs and distance = 450 miles
The distance travelled both the times is same,
So as per the data we have,
Distance = speed *time, so
So, if the train travels at 100 m/h then it reaches, 30 min late i.e
D = 100 *(T+0.5) 30 min = 0.5hr
if the train travels at 120 m/h then it reaches, 15 min early i.e
D = 120 *(T-0.25) 15 min = 0.25hr
so, solving both the equations, we have
100*(T+0.5) = 120*(T-0.25)
T= 4hrs and distance = 450 miles
16 Sep 2011, 05:37
Kudos
Bookmarks
Thanks 
i failed to consider 30 mins = 0.5 hr
i failed to consider 30 mins = 0.5 hr
