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Why 9*8 not considered

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Why 9*8 not considered

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8*9 is counted, so no need to consider 9*8 because both give the same value for pq.
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧




Given that p and q are integers and |p – 9| < 2 and |q – 7| ≤ 2, and we need to find how many values are possible for pq which are either multiple of only 3 or only 5?

Simplifying |p – 9| < 2
=> -2 < p - 9 < 2

Adding 9 on all the sides we get
-2 + 9 < p < 2 + 9
=> 7 < p < 11

Now, p is an integer
=> Possible values of p are 8, 9, 10

Simplifying |q – 7| ≤ 2
=> -2 ≤ q - 7 ≤ 2

Adding 7 on all the sides we get
-2 + 7 ≤ q ≤ 2 + 7
=> 5 ≤ q ≤ 9

Now, q is an integer
=> Possible values of q are 5, 6, 7, 8 , 9

Possible for pq which are either multiple of only 3 or only 5

For, p = 8,
q can be any number which is a multiple of 3 or 5
=> q = 5, 6, 9
=> 3 cases

For p = 9,
As p is a multiple of 3 so q can be any number which is NOT a multiple of 5 and which does not give any value of pq which is achieved above.
=> q = 6, 7, 9 (as q=8 will make pq=72, which is same as p = 8 and q = 9)
=> 3 cases

For p = 10,
As p is a multiple of 5, so q can be any number which is NOT a multiple of 3 and which does not give any value of pq which is achieved above.
=> q = 5, 7, 8
=> 3 cases

=> 9 cases in total

So, Answer will be A
Hope it helps!

Watch the following video to learn the Basics of Absolute Values

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