r=x/z, s=y/z , x, y, z are positive integers. Is z the

Question

r=x/z, s=y/z , x, y, z are positive integers. Is z the greatest one among x, y, z?

1) r<x
2) s<1

Zooroopa · Answer

(I) gives z > 1 (x is a positive integer)
(II) gives y < z

So combining them we do not get any information on x. So it is  E .

consultinghokie · Answer

A. Stmt 1: if r < x then, x > z. so we can answer the question, is z the greatest among x, y, z. It clearly is not the greatest. SUFF Stmt 2: if s < 1 then, z > y. but we don't know about x. INSUFF

Zooroopa · Answer

Could you please explain this part?

ikaytas · Answer

if r < x then, x > z. This holds true only when r is a positive integer greater than 1. It has not been mentioned that r is even an integer. If x=3 and z=5, then r = 0.6, which may be possible. Hence stmt 1 is insuff.
Again, stmt 2 confirms that y<z.
Combining doesn't helo either. Hence, I would go for (E).

Dilshod · Answer

The answer is E.
Statement 1 is insufficient.: rz=x, if all numbers were positive integers and if r<x, than z must have been lesser than x. but since we don't know what number is r, it is insuff.
Statement 2 is also insufficient. s=y/z, s<1, it means that z>y. But we don’t know anything about r and x.

sm176811 · Answer

Agreed actually, It shud be A... Forgot the 'positive integers' part!

mattflow · Answer

r=x/z & rz, since x and z are positive integers s=y/z and s<1 means that z>y since y and z are positive integers combining both we get y

FN · Answer

OK Lets see...

x, y and z are all positive and are integers...so no decimals etc...

1) r<x, which means that x<z (insuff we dont know if y is greater than x or not) 

2) s<1, which means... y<z (remember we are dealing with + integers only)
 but we dont know anythning about X...so Insuff

1+2, we know that x<z; y<z, then Z is the GREATEST...just dont know if y is greater than X or not..but still Z is the greatest amongst the three...

C it is..

Dilshod · Answer

in that case it is A indeed:
Statement 1 is sufficient.: rz=x, if all 3 numbers are positive integers and if r<x, than z must be lesser than x. Hence, z is not the greatest one.

kook44 · Answer

I get E.

from the stem, we know r=x/z, and x & z are positive integers.
from (1):
r<x
say x=1, z=9, thus: r=1/9 - all conditions hold
say x=6, z=5, thus: r=6/5 - all conditions hold.

We still don't know if z>x or vice versa.

(2) lest us know that x > y

combined still can't determine z>x

mendiratta_1812 · Answer

It can't be A.
z = x/r. Suppose, x = 6 & r = 2. In this case z = 3 which is less than x (6).
Suppose, x = 2& r = 1. In this case z = 2 which is equal to x (2).
So we conclude from the 1st statement that, z>1 instead of z>x.
Now, from second we conclude that z > y as s< 1. 
So I think the answer should be  E .

Dilshod · Answer

r=x/z rz=x. all of them are pos.integers. hence, max.value for z is equal to x, BUT not greater than x. sufficient.

the author said that he made a mistake by not saying that r and s are also pos.integers. but in that case we don't need any statements. the question itself contains the answer.

Author, please revise the question

trivikram · Answer

It is A....


Dont even go to the 2nd choice

Consider choice 1

r<x

we dont know about r (if it is a decimal or whole number)

lets say r = 0.2 so possibly x = 2 and z =10
 
Now take r = 5 possible value of x = 25 and z =5 

So we cannot relate x to z concretely)

Now come to choice (2) 

s<1 So we can say that y<z

But the 1st choice is ruled out and the second choice is of least/no help

So the best answer is E ('cos though choice 2 gave an indication of relationship between y and z it was of no help for establsihing the stature of x).

A is wrong because until you look at B you cannot deduce the relationships.

C is also wrong because still the situation is obscure.

ywilfred · Answer

St1:
Does not tell us anything about y and z. Insufficient.

St2:
s < 1. So y < z. But we do not know anything about x. Insufficient.

Using St1 and St2:
We know r<x.

If x = 180, z = 100, r < x, but z < x.
If x = 180, z = 1000, r < x, but z > x.

St 2 does not help us solve the relationship between z and x. Insufficint.

Ans E

r=x/z, s=y/z , x, y, z are positive integers. Is z the

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