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Originally posted by VenoMfTw on 05 Aug 2015, 06:38.
Last edited by Bunuel on 16 Aug 2015, 11:34, edited 1 time in total.
Renamed the topic and edited the question.
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Difficulty:
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47%
(02:33)
correct 53%
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Rakesh is standing 3 steps to the right of a Green mark and 2 steps to the left of a Pink mark. He tosses a coin. If it comes up heads, he moves one step to the left. If it comes up tails he moves one step to the right. He keeps doing this until he reaches one of the two marks, and then he stops. At which mark does he stop?
(1) He stops after 21 coin tosses. (2) He obtains three more heads than tails.
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Rakesh is standing 3 steps to the right of a Green mark and 2 steps to the left of a Pink mark. He tosses a coin. If it comes up heads, he moves one step to the left. If it comes up tails he moves one step to the right. He keeps doing this until he reaches one of the two marks, and then he stops. At which mark does he stop?
A. He stops after 21 coin tosses. B. He obtains three more heads than tails.
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OA : D
G _ _ R _ P If you observe : No. of steps required to reach Pink mark = 2 (Two steps right) = 4 (One step left and 3 steps right) = 6 (Two steps left and 4 steps right) and so on...considering alternate left and right we can further the count
Similarly No. of steps required to reach Green mark = 3 (Three steps left) = 5 (1 right and 4 left) and so on...considering alternate right and left we can further the count
Thus from observation:- If total number of steps is even then destination is Pink. If odd then Green
Statement 1: He stops after 21 coin tosses.
Odd = Green. Hence suff
Statement 2 : He obtains three more heads than tails
T+3 = H Total no of tosses will be = H(no. of heads) + T(no. of tails) Total no. of tosses = 2T + 3 2T = even number 3 = odd number Even num + odd num = odd num Odd = Green. Hence suff
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