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Randy can run pi meters every 2 seconds. If the circular track has a r

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Bunuel
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Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   02 Jul 2015, 01:28
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Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many seconds does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

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C
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   02 Jul 2015, 03:26
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Length of track = 2πr = 2*75*π = 150π m -------- (1)

Speed = π m in 2 secs = π/2 m per sec ------------ (2)

Total distance = 2 * Length of track = 300π ---------- (3)

Time = dist/speed = 300π/(π/2) = 600.
Hence C !!
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   02 Jul 2015, 03:27
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Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


Rate = \(\pi\) meters every 2 seconds = \(\pi / 2\) meters every seconds.
Perimeter of Circular Track = \(\pi\)*Diameter = \(2*75*\pi\) = \(150* \pi\)

Total Distance to be run = \(2*150* \pi\) = \(300* \pi\)

Time = \(300* \pi\) / \(\pi / 2\) second = 600 seconds = 600/60 Mins = 10 Mins

Answer: Option C

But the options should have been in minutes as per the language of the question
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Jul 2015, 09:00
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speed = pi/2 m/sec

Circumference = 2 pi r = 2*pi*75=150 pi

required length = 2 *150*pi

time = 2*150*pi / Pi/2
= 600 seconds

Answer C
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Jul 2015, 09:17
Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


Bunuel, the question asks about minutes while the options are in seconds. Please correct one of them.

\(\pi\) m in 2 seconds are run by Randy. Distance to be covered to run twice around the track : \(2*2*\pi*r\), as circumference of a circle = 2*\pi*r

Given, r=75 m,

Thus total distance to be covered = \(300\pi\)

Speed = \(\pi/2 ms^{-1}\)

Thus, time = distance/speed = \(300\pi\)/\(\pi/2 ms^{-1}\) = 600 seconds = 10 minutes , C is the correct answer
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   04 Jul 2015, 12:23
Option C is correct
speed = pi/2 m/sec

Circumference = 2 pi r = 2*pi*75=150 pi

required length = 2 *150*pi

time = 2*150*pi / Pi/2
= 600 seconds
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   06 Jul 2015, 06:56
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Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


The distance around the track is the circumference of the circle:

\(C = 2\pi r = 150\pi\)

Running twice around the circle would equal a distance of \(300\pi\) meters. If Randy can run \(\pi\) meters every 2 seconds, he runs \(30\pi\) meters every minute. Therefore, it will take him 10 minutes to run around the circular track twice.

Answer: C.
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Aug 2018, 06:59
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Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


Dear Moderator,
Came across this good question while going through the forum, there may have been a small oversight here. Question asks how many minutes does does it take Randy ....? But option are given in seconds , is this ok? Thank you.
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Aug 2018, 07:05
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stne wrote:
Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


Dear Moderator,
Came across this good question while going through the forum, there may have been a small oversight here. Question asks how many minutes does does it take Randy ....? But option are given in seconds , is this ok? Thank you.

________________
Edited. Thank you.
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Aug 2018, 08:11
Sorry..it's C.. 600

Sent from my SM-G610F using GMAT Club Forum mobile app
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   03 Aug 2018, 09:28
Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many seconds does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


The Circumference of the circle = \(2*π*75\)

Distance covered by Randy is 2*\(2*π*75\) = \(4*π*75\)

The speed of Randy is \(\frac{π}{2}\)

Time taken to cover the distance is \(\frac{4*π*75*2}{π}\) = 600 Seconds, Answer must be (C)
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   18 Sep 2019, 09:57
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Bunuel wrote:
Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many seconds does it take Randy to run twice around the track?

A. 150 seconds
B. 300 seconds
C. 600 seconds
D. 1200 seconds
E. 22500 seconds

Kudos for a correct solution.


The circumference of the circular track is 2 x π x 75 = 150π, and Randy’s rate is π/2 meters per second. So it will take Randy 2 x 150π / (π/2) = 300π x 2/π = 600 seconds to run around the track twice.

Answer: C
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   29 Dec 2020, 15:49
We know that the track radius is 75
Now, we want to know the circumference of the track :
C=2*n*r
=2*n*75
=150*n
Because Randy runs twice the track, the distance becomes 2*150*n=300*n

Randy's rate is n every 2 seconds, therefore it is 30*n every minute and 300*n every 10 minutes
Therefore he completes his run in 10 minutes which is 600 seconds (10*60 seconds)

Answer C)
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink] New post   10 Jul 2021, 12:15
The distance around the track is the circumference of the circle:
C = 2pir
= 150pi
Running twice around the circle would equal a distance of 3007T meters. If Randy can run n meters
every 2 seconds, he runs 307T meters every minute. Therefore, it will take him 10 minutes to run around
the circular track twice.
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r [#permalink]
10 Jul 2021, 12:15
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