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Randy can run pi meters every 2 seconds. If the circular track has a r
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02 Jul 2015, 00:28
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72% (01:09) correct 28% (01:17) wrong based on 233 sessions
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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02 Jul 2015, 02:26
Length of track = 2πr = 2*75*π = 150π m  (1)
Speed = π m in 2 secs = π/2 m per sec  (2)
Total distance = 2 * Length of track = 300π  (3)
Time = dist/speed = 300π/(π/2) = 600. Hence C !!



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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02 Jul 2015, 02:27
Bunuel wrote: Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?
A. 150 seconds B. 300 seconds C. 600 seconds D. 1200 seconds E. 22500 seconds
Kudos for a correct solution. Rate = \(\pi\) meters every 2 seconds = \(\pi / 2\) meters every seconds. Perimeter of Circular Track = \(\pi\)*Diameter = \(2*75*\pi\) = \(150* \pi\) Total Distance to be run = \(2*150* \pi\) = \(300* \pi\) Time = \(300* \pi\) / \(\pi / 2\) second = 600 seconds = 600/60 Mins = 10 Mins Answer: Option CBut the options should have been in minutes as per the language of the question
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Jul 2015, 08:00
speed = pi/2 m/sec Circumference = 2 pi r = 2*pi*75=150 pi required length = 2 *150*pi time = 2*150*pi / Pi/2 = 600 seconds Answer C
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Jul 2015, 08:17
Bunuel wrote: Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?
A. 150 seconds B. 300 seconds C. 600 seconds D. 1200 seconds E. 22500 seconds
Kudos for a correct solution. Bunuel, the question asks about minutes while the options are in seconds. Please correct one of them. \(\pi\) m in 2 seconds are run by Randy. Distance to be covered to run twice around the track : \(2*2*\pi*r\), as circumference of a circle = 2*\pi*r Given, r=75 m, Thus total distance to be covered = \(300\pi\) Speed = \(\pi/2 ms^{1}\) Thus, time = distance/speed = \(300\pi\)/\(\pi/2 ms^{1}\) = 600 seconds = 10 minutes , C is the correct answer



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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04 Jul 2015, 11:23
Option C is correct speed = pi/2 m/sec
Circumference = 2 pi r = 2*pi*75=150 pi
required length = 2 *150*pi
time = 2*150*pi / Pi/2 = 600 seconds



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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06 Jul 2015, 05:56



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Aug 2018, 05:59
Bunuel wrote: Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many minutes does it take Randy to run twice around the track?
A. 150 seconds B. 300 seconds C. 600 seconds D. 1200 seconds E. 22500 seconds
Kudos for a correct solution. Dear Moderator, Came across this good question while going through the forum, there may have been a small oversight here. Question asks how many minutes does does it take Randy ....? But option are given in seconds , is this ok? Thank you.
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Aug 2018, 06:05



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Aug 2018, 07:11
Sorry..it's C.. 600 Sent from my SMG610F using GMAT Club Forum mobile app



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Re: Randy can run pi meters every 2 seconds. If the circular track has a r
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03 Aug 2018, 08:28
Bunuel wrote: Randy can run \(\pi\) meters every 2 seconds. If the circular track has a radius of 75 meters, how many seconds does it take Randy to run twice around the track?
A. 150 seconds B. 300 seconds C. 600 seconds D. 1200 seconds E. 22500 seconds
Kudos for a correct solution. The Circumference of the circle = \(2*π*75\) Distance covered by Randy is 2*\(2*π*75\) = \(4*π*75\) The speed of Randy is \(\frac{π}{2}\) Time taken to cover the distance is \(\frac{4*π*75*2}{π}\) = 600 Seconds, Answer must be (C)
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Re: Randy can run pi meters every 2 seconds. If the circular track has a r &nbs
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