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Rank those three in order from smallest to biggest.
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Updated on: 05 Dec 2012, 12:52
2
5
00:00
A
B
C
D
E
Difficulty:
55% (hard)
Question Stats:
60% (01:46) correct 40% (01:49) wrong based on 367 sessions
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Remember, like all GMAT Quantitative problems, this is a no calculator problem.
I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, II
For a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/number-sense-for-the-gmat/ Experts, feel free to share you thoughts on what number sense is and how to develop it.
all fractions are close to 1/3 So if we take each \(I. 47/150<50/150=1/3\) \(II. 111/330>110/330=1/3\) \(III. 299/900<300/900=1/3\) Now between II and III we can easily figure out that 299 is closer to 300 than \(47*3\). So III>I So the correct order from smallest to largest is : \(I>III>II\) So shouldn't it be B?
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So the correct order from smallest to largest is : \(I>III>II\) So shouldn't it be B?
Yes, you are 100% correct. I changed this in the problem above. I said "smallest to largest", but then when I did it in my head, I put them in order from largest to smallest! Sorry about any confusion. Mike _________________
Re: Rank those three in order from smallest to biggest.
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19 Dec 2012, 05:28
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I. 47/150 is almost 50/150 = 1/3. It is (50-47)/150 = 3/150 = 1/50 away from 1/3 II. 111/330 is beyond 110/330 = 1/3 III. 299/900 is almost 300/900 = 1/3. 299/900 is (300-299)/900 = 1/900 away from 1/3
I is the farther to the left of 1/3 than III while II is the largest.
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19 Dec 2012, 06:54
Try and get all the denominators the same, i.e. in terms of 900:
I: 47x6/150x6 = 282/900
II: 111x3/330x3 =:(approx) 333/990
III: 299/900
From the above, we know that I is the smallest (as it has the smallest numerator) and hence comes first, eliminate options C,D and E. Only left with A & B.
299/900 will definitely be greater than 333/990 as if we find the accurate multiple by which to get 900 in II, it will give us a numerator being less than 299. Hence III<I
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: Rank those three in order from smallest to biggest.
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23 Oct 2017, 01:58
mikemcgarry wrote:
Remember, like all GMAT Quantitative problems, this is a no calculator problem.
I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, II
For a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/number-sense-for-the-gmat/ Experts, feel free to share you thoughts on what number sense is and how to develop it.
I. 47/150 = 282/900 II. 333/990 >330/990=1/3= 300/900 III. 299/900
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Rank those three in order from smallest to biggest.
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23 Oct 2017, 02:01
mikemcgarry wrote:
Remember, like all GMAT Quantitative problems, this is a no calculator problem.
I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, II
For a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/number-sense-for-the-gmat/ Experts, feel free to share you thoughts on what number sense is and how to develop it.
It can also be solved by reducing the values. So, I. 47/150 << 50/150 =1/3 II. 111/330 > 110/330 = 1/3 III. 299/900 just< 300/900 = 1/3
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60% (01:46) correct 
