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Magoosh GMAT Instructor
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Rank those three in order from smallest to biggest.
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Updated on: 05 Dec 2012, 11:52
Question Stats:
61% (01:46) correct 39% (01:48) wrong based on 376 sessions
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Remember, like all GMAT Quantitative problems, this is a no calculator problem. I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, IIFor a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/numbersenseforthegmat/Experts, feel free to share you thoughts on what number sense is and how to develop it.
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Mike McGarry Magoosh Test Prep
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Originally posted by mikemcgarry on 05 Dec 2012, 11:32.
Last edited by mikemcgarry on 05 Dec 2012, 11:52, edited 1 time in total.



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Re: number sense problem, estimation
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05 Dec 2012, 11:44



Magoosh GMAT Instructor
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Re: number sense problem, estimation
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05 Dec 2012, 11:53
souvik101990 wrote: So the correct order from smallest to largest is : \(I>III>II\) So shouldn't it be B? Yes, you are 100% correct. I changed this in the problem above. I said "smallest to largest", but then when I did it in my head, I put them in order from largest to smallest! Sorry about any confusion. Mike
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Re: Rank those three in order from smallest to biggest.
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19 Dec 2012, 04:28
I. 47/150 is almost 50/150 = 1/3. It is (5047)/150 = 3/150 = 1/50 away from 1/3 II. 111/330 is beyond 110/330 = 1/3 III. 299/900 is almost 300/900 = 1/3. 299/900 is (300299)/900 = 1/900 away from 1/3 I is the farther to the left of 1/3 than III while II is the largest. Rank: I,III,II
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Re: Rank those three in order from smallest to biggest.
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19 Dec 2012, 05:54
Try and get all the denominators the same, i.e. in terms of 900:
I: 47x6/150x6 = 282/900
II: 111x3/330x3 =:(approx) 333/990
III: 299/900
From the above, we know that I is the smallest (as it has the smallest numerator) and hence comes first, eliminate options C,D and E. Only left with A & B.
299/900 will definitely be greater than 333/990 as if we find the accurate multiple by which to get 900 in II, it will give us a numerator being less than 299. Hence III<I
Final order: I,III,II
Option B



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Re: Rank those three in order from smallest to biggest.
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23 Oct 2017, 00:58
mikemcgarry wrote: Remember, like all GMAT Quantitative problems, this is a no calculator problem. I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, IIFor a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/numbersenseforthegmat/Experts, feel free to share you thoughts on what number sense is and how to develop it. I. 47/150 = 282/900 II. 333/990 >330/990=1/3= 300/900 III. 299/900 So, II >III>I or as per mikemcgarry I< III < II Answer B
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Rank those three in order from smallest to biggest.
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23 Oct 2017, 01:01
mikemcgarry wrote: Remember, like all GMAT Quantitative problems, this is a no calculator problem. I. \(\frac{47}{150}\)
II. \(\frac{111}{330}\)
III. \(\frac{299}{900}\)
Rank those three in order from smallest to biggest. (A) I, II, III (B) I, III, II (C) II, I, III (D) II, III, I (E) III, I, IIFor a full discussion of this question and the topic of number sense, see this blog: http://magoosh.com/gmat/2012/numbersenseforthegmat/Experts, feel free to share you thoughts on what number sense is and how to develop it. It can also be solved by reducing the values. So, I. 47/150 << 50/150 =1/3 II. 111/330 > 110/330 = 1/3 III. 299/900 just< 300/900 = 1/3 So, II >III>I or as per mikemcgarry I< III < II Answer B
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Rank those three in order from smallest to biggest.
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04 Jun 2018, 05:44
I. \(\frac{47}{150}\) =50/1503/150=1/31/50
II. \(\frac{111}{330}\)=110/330+1/330=1/3+1/330
III. \(\frac{299}{900}\)=300/9001/900=1/31/900
Answer (B) I, III, II




Rank those three in order from smallest to biggest.
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