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10 Apr 2014, 10:36
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Veritas Prep Book 2 - page 228 - Q# 81 Answer is D - but not sure how to get answer
81)
The ratio of men to women at a picnic is 7:5 and the ratio of men to children at that picnic is 3:4. What is the smallest total number of men and women and children that could be at the picnic?
a) 18
b) 36
c) 54
d) 64
e) 128
81)
The ratio of men to women at a picnic is 7:5 and the ratio of men to children at that picnic is 3:4. What is the smallest total number of men and women and children that could be at the picnic?
a) 18
b) 36
c) 54
d) 64
e) 128
10 Apr 2014, 13:43
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jasdhanda
Hi,
As m:w = 7:5, lets say m = 7x & w = 5x
AS m:c = 3:4, lets say m = 3y & c = 4y
Now 7x = 3y => x/y = 3/7
the min value which x can take is 3 and minimum which y can take is 7
so m = 7*3 = 21
w = 5*3 = 15
c = 4*7 = 28
m+w+c = 64
Answer is D.
03 Jan 2016, 15:02
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A slightly faster way (and I think easier).
M:W = 7:5
M:C = 3:4
Somewhat becomes simultaneous equation where
# children = 4/3 * Men
M:W:C = 7:5:(4/3 * 7) => 7:5:(28/3) => 7x3 : 5x3 : 28
M:W:C = 21:15:28
total = 21 + 15 + 28 = 64 (D)
M:W = 7:5
M:C = 3:4
Somewhat becomes simultaneous equation where
# children = 4/3 * Men
M:W:C = 7:5:(4/3 * 7) => 7:5:(28/3) => 7x3 : 5x3 : 28
M:W:C = 21:15:28
total = 21 + 15 + 28 = 64 (D)
