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11 Jun 2014, 21:31
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Guys, you might find this interesting. I live in a 4br apartment in NYC. As can happen, one of my roommates has discovered bed bugs. I'm told that they spread quickly and that 30 percent of people do not show signs of being bitten by bed bugs. So I'm trying to figure out what the probability of at least 1 of us other 3 roommates not showing marks is, assuming that the bugs have already spread to us. I got 66%. Is that correct? I did probability of 1 plus probability of 2 plus probability of all 3.
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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11 Jun 2014, 23:20
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vandygrad11
Yes, you are correct.
P(No signs though bitten) = .3
P(Signs after bitten) = .7
Assuming bugs have spread to the whole house and all of you are being bitten,
P(All 3 will show signs) = .7*.7*.7 = .343
P(At least one of you will not show signs) = 1 - .34 = .66
13 Jun 2014, 21:57
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Yay math! Thank you.
The exterminator is doing his job!
The exterminator is doing his job!
VeritasPrepKarishma
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
