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Red, white, blue, and black balls are arranged in a row such that the

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Red, white, blue, and black balls are arranged in a row such that the  [#permalink]

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New post 24 Oct 2017, 00:00
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E

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Question Stats:

76% (01:57) correct 24% (01:38) wrong based on 65 sessions

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Red, white, blue, and black balls are arranged in a row such that the pattern of red followed by white, white followed by blue, blue followed by black, and black followed by red is maintained. What is the color of the first ball in the row?

(1) 11th ball is neither red nor white.
(2) 12th ball is neither blue nor black

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Re: Red, white, blue, and black balls are arranged in a row such that the  [#permalink]

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New post 24 Oct 2017, 00:22
1
nkmungila wrote:
Red, white, blue, and black balls are arranged in a row such that the pattern of red followed by white, white followed by blue, blue followed by black, and black followed by red is maintained. What is the color of the first ball in the row?

(1) 11th ball is neither red nor white.
(2) 12th ball is neither blue nor black


It should be C

1- It could still be black and blue which gives us 2 options for the first ball. - Not Sufficient
2- It could then be red and white which would again give us two options for the first ball - Not Sufficient

Combining 1 and 2

- From 1, we know 11th ball can be blue or black, but if it is black, 12th ball has to be blue (as per the order given), but statement 2 says 12th ball cannot be blue. This suggests, 11th ball must be blue with 10th ball being black. This gives us the order we need to back traverse and find the color of the first ball.
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Re: Red, white, blue, and black balls are arranged in a row such that the  [#permalink]

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New post 24 Oct 2017, 10:30
jedit wrote:
nkmungila wrote:
Red, white, blue, and black balls are arranged in a row such that the pattern of red followed by white, white followed by blue, blue followed by black, and black followed by red is maintained. What is the color of the first ball in the row?

(1) 11th ball is neither red nor white.
(2) 12th ball is neither blue nor black


It should be C

1- It could still be black and blue which gives us 2 options for the first ball. - Not Sufficient
2- It could then be red and white which would again give us two options for the first ball - Not Sufficient

Combining 1 and 2

- From 1, we know 11th ball can be blue or black, but if it is black, 12th ball has to be blue (as per the order given), but statement 2 says 12th ball cannot be blue. This suggests, 11th ball must be blue with 10th ball being black. This gives us the order we need to back traverse and find the color of the first ball.



If 11th ball is blue how can 12th ball be black, it should be red isn't it? Also statement 2 says 12th ball cannot be black but black follows blue. So if 11th ball is blue 12th cannot be black and hence both the statements are not sufficient to answer the question. IMO it should be E.
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Re: Red, white, blue, and black balls are arranged in a row such that the &nbs [#permalink] 24 Oct 2017, 10:30
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