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17 Nov 2021, 04:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (02:05) correct
30%
(02:32)
wrong
based on 125
sessions
History
Date
Time
Result
Not Attempted Yet
Richard leaves to visit his friend who lives 200 miles down Interstate 10. One hour later his friend Steve leaves to visit Richard via Interstate 10. If Richard drives at 60 mph and Steve drives at 40 mph, how many miles will Steve have driven when they cross paths?
(A) 56
(B) 58
(C) 60
(D) 65
(E) 80
(A) 56
(B) 58
(C) 60
(D) 65
(E) 80
17 Nov 2021, 04:55
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Richard starts his journey and then his friend Steve starts it 1 hour later. Richard covers 60 miles in 1 hour hence the new distance between them, when Steve begins, is 140 miles
Now let time taken be x
60x + 40x = 140
=> x = 1.4 hours
Now Steve travels 40x miles = 40 x 1.4 = 56 miles.
Option A
Now let time taken be x
60x + 40x = 140
=> x = 1.4 hours
Now Steve travels 40x miles = 40 x 1.4 = 56 miles.
Option A
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17 Nov 2021, 05:12
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Option (A)
Distance covered by Richard in one hour = d = s * t = 60 * 1 = 60 miles.
Richard and Steve now meet at some point in the remaining distance 200 - 60 = 140 miles.
So, they together cover this distance with relative speed of 60+40 = 100 miles/hr.
Time taken to cover this distance = \(\frac{140}{100}\) = \(\frac{7}{5}\) hrs.
Distance covered by Steve in this time = \(\frac{7}{5}\) * 40 = 7 * 8 = 56 miles.
Distance covered by Richard in one hour = d = s * t = 60 * 1 = 60 miles.
Richard and Steve now meet at some point in the remaining distance 200 - 60 = 140 miles.
So, they together cover this distance with relative speed of 60+40 = 100 miles/hr.
Time taken to cover this distance = \(\frac{140}{100}\) = \(\frac{7}{5}\) hrs.
Distance covered by Steve in this time = \(\frac{7}{5}\) * 40 = 7 * 8 = 56 miles.
