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Roger wants to buy a television and DVD player. There are 9 available

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Roger wants to buy a television and DVD player. There are 9 available  [#permalink]

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New post Updated on: 09 Apr 2018, 01:23
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Difficulty:

  25% (medium)

Question Stats:

84% (01:08) correct 16% (01:39) wrong based on 50 sessions

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Roger wants to buy a television and DVD player. There are 9 available models of televisions and 6 available models of DVD players, but 3 of these television sets are not compatible with 2 of the DVD players. In how many ways can he buy a television and a compatible DVD player?

a. 48
b. 54
c. 62
d. 70
e. 72

Source- Time4education

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Originally posted by Nixondutta on 08 Apr 2018, 23:53.
Last edited by Bunuel on 09 Apr 2018, 01:23, edited 1 time in total.
Edited the question.
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Re: Roger wants to buy a television and DVD player. There are 9 available  [#permalink]

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New post 09 Apr 2018, 00:12
Nixondutta wrote:
Roger wants to buy a television and DVD player. There are 9 available models of televisions and 6 available models of DVD players, but 3 of these television sets are not compatible with 2 of the DVD players. In how many ways can he buy a television and a compatible DVD player?
Source- Time4education


a.48
b.54
c.62
d.70
e.72


Total number of ways of selecting one TV and one DVD
=9C1*6C1
Total number of ways of selecting not compatible TV and DVD players=3c1*2C1

many ways can he buy a television and a compatible DVD player=9C1*6C1-3c1*2C1=48

Ans A
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Re: Roger wants to buy a television and DVD player. There are 9 available  [#permalink]

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New post 09 Apr 2018, 21:59
Nixondutta wrote:
Roger wants to buy a television and DVD player. There are 9 available models of televisions and 6 available models of DVD players, but 3 of these television sets are not compatible with 2 of the DVD players. In how many ways can he buy a television and a compatible DVD player?

a. 48
b. 54
c. 62
d. 70
e. 72

Source- Time4education


Ways of selecting from the total = 9C1 * 6C1 =54
Ways if selecting not compatible product = 3C1 * 2C1 =6

Therefore Ways of selecting compatible products =54 - 6 =48
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Re: Roger wants to buy a television and DVD player. There are 9 available  [#permalink]

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New post 19 Apr 2018, 03:37
2
Roger wants to buy a television and DVD player. There are 9 available models of televisions and 6 available models of DVD players, but 3 of these television sets are not compatible with 2 of the DVD players. In how many ways can he buy a television and a compatible DVD player?

a. 48
b. 54
c. 62
d. 70
e. 72

If you are in time crunch then we know that there are 54 total ways and there is just one option which is less than 54. So that has to be the answer.
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Re: Roger wants to buy a television and DVD player. There are 9 available  [#permalink]

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New post 23 Apr 2018, 16:51
1
Nixondutta wrote:
Roger wants to buy a television and DVD player. There are 9 available models of televisions and 6 available models of DVD players, but 3 of these television sets are not compatible with 2 of the DVD players. In how many ways can he buy a television and a compatible DVD player?

a. 48
b. 54
c. 62
d. 70
e. 72


If all 9 models of televisions and 6 models of DVD players are compatible with one another, then there are 9 x 6 = 54 ways to purchase them. However, since 3 models of televisions and 2 models of DVD players are not compatible, we need to remove 3 x 2 = 6 ways from the above mentioned 54 ways, leaving us with 54 - 6 = 48 ways to purchase a TV and a DVD player.

Answer: A
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Re: Roger wants to buy a television and DVD player. There are 9 available &nbs [#permalink] 23 Apr 2018, 16:51
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