pintukr
Rohan took pure milk and started to dilute it with water. He first replaced 16 liters from the beaker full of pure milk with 16 liters of water. He performed this process three more times. Finally, the ratio of milk left in the beaker to that of water became 81 : 175. Find out how much pure milk (in liters) was there in the beaker initially?
A. 48
B. 64
C. 72
D. 84
E. 96
from Unacademy Prep
Not a 'GMAT-like' question IMO
Ratio of milk left to the ratio of milk originally present = \((1-\frac{16}{x})^4\)
Let's assume that the beaker contained 81 + 175 = 256 units of liquid at the start of the mixing process. It's given that the beaker consisted of pure milk, hence all 256 units of liquid were pure milk.
Units of pure milk post the mixing process = 81 (given that
ratio of milk left in the beaker to that of water became 81 : 175)
\(\frac{81}{256} = (1-\frac{16}{x})^4\)
Taking the fourth root on both sides of the equation
\(\frac{3}{4} = 1-\frac{16}{x}\)
\(\frac{16}{x} = 1 - \frac{3}{4}\)
\(x = 16 * 4 = 64\)
Option B