Roma was watering her garden with the help of a watering can.

Why 44.625
Before watering second plant can has 85 unit water. So should we devide 44.625 which is left at the end into 85?
I mean the answer is D, 52.5%

Let water in can be 100 ml

Water left after pouring 15% => 15 ml on first plant = 85 ml

Water left after pouring 25% of 85 => 21.25 ml on second plant = 85 - 21.25 ml = 63.75 ml

Water left after pouring 30% of 63.75 on third plant = 0.7 * (63.75) ml = 44.625 ml

Now we need to find what % of water remaining before watering second plant is left in the can => we can see that 44.425 is just over 50% of 85, the only option that fits is D. 52.500%

Answer D.

Let's assume the can initially contains 100 units of water.

Water poured on the first plant: 15% of the water in the can.
15% of 100 = 15 units.
After watering the first plant, the remaining water in the can is: 100−15=85 units.

Water poured on the second plant: 25% of the remaining water (85 units) in the can.
25% of 85 = 21.25 units.
After watering the second plant, the remaining water in the can is: 85−21.25 = 63.75 units.

Water poured on the third plant: 30% of the remaining water (63.75 units) in the can.
30% of 63.75 = 19.125 units.
After watering the third plant, the remaining water in the can is: 63.75−19.125=44.625 units.

Now, we need to find the water left inside the can after the third plant is what percentage of the water left just before watering the second plant.

The remaining water after watering the third plant is 44.625 units, and the remaining water just before watering the second plant is 85 units.
The percentage is calculated as:
(44.625/85) × 100 ≈ 52.5%.
Therefore, the answer is D.

Total 100	1st	2nd	3rd
Poured	15	(85 * .25) = 85/4	85*3*3/4*10
Remaining	85	85*3/4

85*3*7/4*10

Required Value = ([ (85 * 3 * 7) ][ (4*10*85) ]) * 100 = 52%

Remaining after 1 = 85/100
After 2= 85/100 * 3/4
After 3 = 85/100 * 3/4 * 7/10 = 357/800

Percentage at end over after 1st = [357/800 / 85/100] * 100
52.5%