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07 Feb 2020, 06:18
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (01:55) correct
26%
(01:47)
wrong
based on 246
sessions
History
Date
Time
Result
Not Attempted Yet
Rose walked along a track at an average speed of 100 meters per minute. Was the length of the track greater than half a kilometer? (1 kilometer = 1000 meters)
(1) She took less than 400 seconds to cover the track.
(2) She took more than 320 seconds to cover the track
(1) She took less than 400 seconds to cover the track.
(2) She took more than 320 seconds to cover the track
07 Feb 2020, 12:01
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question is only asking if she walked more than half a kilometer, therefore you only need to find the lower bound.
1. is the upper bound. insuff
2. is the lower bound
320 seconds = 5 mins 20 seconds
5.333 mins x 100m per min = 533.33
answer B
1. is the upper bound. insuff
2. is the lower bound
320 seconds = 5 mins 20 seconds
5.333 mins x 100m per min = 533.33
answer B
08 Feb 2020, 12:34
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Bunuel
Solution
Step 1: Analyse Question Stem
- • Average speed is 100 meters per minute.
• Let us assume that the length of the track is d (in meters) and time taken to cover the track is t (in minutes).
• So, d = 100*t
- o We need to find if d > 500 meters
o Or, \(100*t > 500\)
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: She took less than 400 seconds to cover the track.
- • According to this statement, \(t < (\frac{400}{60})\) minutes
- o \(t < \frac{20}{3}\)
- o \(100*t < 666.66\)
o So, We cannot be sure if \(100*t > 500\), for example, it can 499 or 501.
Hence, statement 1 is not sufficient and we can eliminate answer options A and D
Statement 2: She took more than 320 seconds to cover the track
- • According to this statement, \(t > (\frac{320}{60})\) minutes
- o \(t > \frac{16}{3}\)
- o \(100*t > 533.33 ⟹ 100*t > 500\)
Thus, the correct answer is Option B.
