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Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can

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Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 23 Apr 2019, 02:24
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

78% (02:05) correct 22% (02:03) wrong based on 32 sessions

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Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 6 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?


(A) Tuesday
(B) Wednesday
(C) Thursday
(D) Friday
(E) Saturday

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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 23 Apr 2019, 02:43
1

Solution


Given:
    • Roy’s cat eats 1/3 of a can of cat food every morning and 1/4 of a can of cat food every evening.
    • Before feeding his cat on Monday morning, Roy opened a box containing 6 cans of cat food.

To find:
    • On what day of the week did the cat finish eating all the cat food in the box?

Approach and Working:
The cat eats 1/3 food in morning and 1/4 food in evening.
    • Hence, in 1 day, the cat consumes = 1/3 + 1/4 = 7/12 of a can
    • Therefore, to consume 6 cans of food, the cat will take 6/(7/12) = 72/7 days = 10.3 days (approx.)

So, starting from Monday, on the 11th day or on Thursday the cat will finish eating all the food.

Hence, the correct answer is option C.

Answer: C

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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 23 Apr 2019, 06:14
Bunuel wrote:
Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 6 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?


(A) Tuesday
(B) Wednesday
(C) Thursday
(D) Friday
(E) Saturday


per day ; 1/4+1/3 ; 7/12
total 6
so it will take ; 6/7/12 ; 72/7 ; ~ 10 days
from monday ; 10th day thursday
IMO C
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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 23 Apr 2019, 06:56
Cat food can =X

1/3(X)= morning
1/4(X)= evening

In a day 7/12(X)

Let X= 12

Roy opened 6 cans on Monday =6x=6*12=72

1 day =7

Mon to mon to Wed = 70

Thursday -only 2 , needed 5 more,

Thursday- answer

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Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 23 Apr 2019, 12:26
Why isn't it Friday? There is still leftover, correct? The sum says " all of the food in the box".
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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 24 Apr 2019, 01:28
Consider 1 can has 12 parts, and cat eats 7 parts in a day out of 12, on Thursday it left with only 2 parts, so it emptied all cans on Thursday morning only ,

Please refer above solution.

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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can  [#permalink]

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New post 25 Apr 2019, 18:52
Bunuel wrote:
Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 6 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?


(A) Tuesday
(B) Wednesday
(C) Thursday
(D) Friday
(E) Saturday


Each day the cat eats 1/3 + 1/4 = 4/12 + 3/12 = 7/12 of a can of cat food. Therefore, 6 cans of cat food can last 6/(7/12) = 72/7 = 10 2/7. That is, a box of 6 cans of cat food can last a little more than 10 days. So the can would finish eating all the cat food in the box on the 11th day and 11 days counting from Monday is Thursday.

Answer: C
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Re: Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can   [#permalink] 25 Apr 2019, 18:52
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