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Running at their respective constant rates, machine X takes [#permalink]

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29 Oct 2008, 23:54

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?

When they work together, the number of widgets produced is (combined rate)*time_taken (X+Y)*3 = 5w/4

substituting X and Y with their rate (w/(t+2) + w/t)*3 = 5w/4

and also, t is a number of days for Y

Didn't get the point man???....you got the same equation as @mbajingle....i think he missed out on 3....rest remains the same

Anyways, thanks for this!

The equation is his, I just quoted to show he missed 3, that will give the incorrect calculation and the other thing is that t is for Y, so after find out t, he will need to add it by 2.