Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
30 Sep 2024, 09:19
Kudos
Bookmarks
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (01:06) correct
50% (00:25) wrong based on 2 sessions
History
Date
Time
Result
Not Attempted Yet
S = {1, 2, 3, 4, 5, 6, 7, 8}
Quantity A
The number of 4-member subsets of S
Quantity B
The number of 5-member subsets of S
Quantity A
The number of 4-member subsets of S
Quantity B
The number of 5-member subsets of S
02 Mar 2025, 11:58
Kudos
Bookmarks
OE
Recall that the number of r-member subsets of a set with n members is equal to \(\frac{n!}{r!(n - r)!}\). So Quantity A is equal to \(\frac{8!}{4! 4!}=\frac{(8)(7)(6)(5)}{(4)(3)(2)(1)} = 70\). Similarly, Quantity B is equal to \(\frac{8!}{5! 3!} =\frac{(8)(7)(6)}{(3)(2)(1)} = 56.\) Thus the correct answer is Choice A.
Answer: A
Recall that the number of r-member subsets of a set with n members is equal to \(\frac{n!}{r!(n - r)!}\). So Quantity A is equal to \(\frac{8!}{4! 4!}=\frac{(8)(7)(6)(5)}{(4)(3)(2)(1)} = 70\). Similarly, Quantity B is equal to \(\frac{8!}{5! 3!} =\frac{(8)(7)(6)}{(3)(2)(1)} = 56.\) Thus the correct answer is Choice A.
Answer: A
