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tarek99
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S= (a-b, b-a, a+b) If the mean of set S is a+b, then median 14 Nov 2008, 01:40
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I have a question guys. I read somewhere that says:

S= (a-b, b-a, a+b)
If the mean of set S is a+b, then median must be 0.

I honestly don't see that. Would someone please explain this concept to me?
Thanks



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S= (a-b, b-a, a+b) If the mean of set S is a+b, then median 14 Nov 2008, 02:40
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Nope, i am not able to understand it either. When you say mean is a+b , that means a+b/3 = a+b which means a+b=0.
By solving for median , we get median = 2b = -2a . I don't understand how it is 0.
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S= (a-b, b-a, a+b) If the mean of set S is a+b, then median 14 Nov 2008, 04:05
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tarek99
I have a question guys. I read somewhere that says:

S= (a-b, b-a, a+b)
If the mean of set S is a+b, then median must be 0.

I honestly don't see that. Would someone please explain this concept to me?
Thanks
Show more

If the mean of set is (a+b), then (a+b) must be the median. (It can't be the max or min of the 3 numbers)
Because a+b=0 so the median is 0
Sorry If I'm wrong, I'm very bad at mean and median....
If I'm right, you guys should listen to David Archuleta Deluxe version :P :x
It's good for our brains. (just kidding)
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S= (a-b, b-a, a+b) If the mean of set S is a+b, then median 14 Nov 2008, 04:21
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gameCode
Nope, i am not able to understand it either. When you say mean is a+b , that means a+b/3 = a+b which means a+b=0.
By solving for median , we get median = 2b = -2a . I don't understand how it is 0.
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then S= {-2a,2a,0}

The order in the list will be
[-2a, 0, 2a] or [2a,0, - 2a] which the median is 0
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S= (a-b, b-a, a+b) If the mean of set S is a+b, then median 11 Mar 2010, 03:06
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It is given that in (a-b, b-a, a+b) a+b is the mean
so,
=> a+b = (a-b+b-a+a+b)/3
=>3a+3b = a+b
=>2a+2b = 0
=> a+b = 0
=> b=-a
If we replace b by -a, our set is actually (a+a), (-a-a), (a-a)
2a, -2a, 0
so median is 0.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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