S and R are two beehives where S contains more bees than that of R.

Let total number of bees in S be x and total number of bees in R be y. Is \(\frac{Honey_R}{y} > \frac{Honey_S}{x}\)?

Statement 1 - Worker bees in R - 40y/100 and worker bees in S - 30x/100

We cannot conclude anything else from this statement, hence this statement is insufficient.

Statement 2 - Honey drops collected in S = 5 * number of worker bees in S and honey drops collected in R = 4 * number of worker bees in R

Cannot calculate total honey collected, hence this statement is insufficient.

Combining both the statements -

Honey drops collected in S = 5 * 30 * x / 100 = 150x/100
Honey drops collected in R = 4 * 40 * y / 100 = 160y/100

Calculating average honey collected -

\(Avg_{S} => \frac{150x/100}{x} = \frac{150}{100}\)
\(Avg_{R} => \frac{160y/100}{y} = \frac{160}{100}\)

\(Avg_{R} > Avg_{S}\) => So, the answer is Yes, both the statements together are sufficient.

Answer: C