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S1 and S2 are two sets containing integers only. If an integer X is

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amanvermagmat
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S1 and S2 are two sets containing integers only. If an integer X is [#permalink] New post   15 Mar 2018, 23:28
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S1 and S2 are two sets containing integers only. If an integer X is randomly selected from S1 and another integer Y is randomly selected from S2, what is the probability that (X+Y) is even?

(1) S1 = {-16, -4, 0, 6, 12}

(2) S2 = {-17, -15, -11, 19, 25}
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amanvermagmat
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Re: S1 and S2 are two sets containing integers only. If an integer X is [#permalink] New post   09 May 2018, 22:59
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amanvermagmat wrote:
S1 and S2 are two sets containing integers only. If an integer X is randomly selected from S1 and another integer Y is randomly selected from S2, what is the probability that (X+Y) is even?

(1) S1 = {-16, -4, 0, 6, 12}

(2) S2 = {-17, -15, -11, 19, 25}


Sum of two integers is even when either both are odd or both are even.

(1) We know all integers of S1 are even, but we dont know about S2. Not sufficient.

(2) We know all integers of S2 are odd, but we dont know about S1. Not sufficient.

Combining, all integers of S1 are even and all integers of S2 are odd. No matter which integer is selected from S1 and which is selected from S2, X+Y will be even+odd = odd, for sure. So the probability that X+Y is even is = 0. Sufficient.

Hence C answer
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Re: S1 and S2 are two sets containing integers only. If an integer X is [#permalink] New post   19 Sep 2019, 07:41
Hi,

I want to understand, if we know All the integer in S1 is even, and no matter y in s2 is odd or even, the x+y will be even. Why we can’t answer A?
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Re: S1 and S2 are two sets containing integers only. If an integer X is [#permalink] New post   20 Sep 2019, 19:47
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anitakhairunnisa wrote:
Hi,

I want to understand, if we know All the integer in S1 is even, and no matter y in s2 is odd or even, the x+y will be even. Why we can’t answer A?


anitakhairunnisa
Hello,
I don't understand when you say no matter y in s2 is odd or even.

Just so we are on the same page, if one term (x) is even then you need to know the value of y is even or odd to determine x+y will be even or odd.
Only an even value when added to even value will result in even. Even value added to odd value will result in odd.
You can always try with easier numbers if you don't want to remember these rules. I still do.

I hope that helps
Thank you!
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Re: S1 and S2 are two sets containing integers only. If an integer X is [#permalink]
20 Sep 2019, 19:47
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