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S1 and S2 are two sets containing integers only. If an integer X is randomly selected from S1 and another integer Y is randomly selected from S2, what is the probability that (X+Y) is even?
(1) S1 = {-16, -4, 0, 6, 12}
(2) S2 = {-17, -15, -11, 19, 25}
(1) S1 = {-16, -4, 0, 6, 12}
(2) S2 = {-17, -15, -11, 19, 25}
09 May 2018, 22:59
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amanvermagmat
S1 and S2 are two sets containing integers only. If an integer X is randomly selected from S1 and another integer Y is randomly selected from S2, what is the probability that (X+Y) is even?
(1) S1 = {-16, -4, 0, 6, 12}
(2) S2 = {-17, -15, -11, 19, 25}
(1) S1 = {-16, -4, 0, 6, 12}
(2) S2 = {-17, -15, -11, 19, 25}
Sum of two integers is even when either both are odd or both are even.
(1) We know all integers of S1 are even, but we dont know about S2. Not sufficient.
(2) We know all integers of S2 are odd, but we dont know about S1. Not sufficient.
Combining, all integers of S1 are even and all integers of S2 are odd. No matter which integer is selected from S1 and which is selected from S2, X+Y will be even+odd = odd, for sure. So the probability that X+Y is even is = 0. Sufficient.
Hence C answer
19 Sep 2019, 07:41
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Hi,
I want to understand, if we know All the integer in S1 is even, and no matter y in s2 is odd or even, the x+y will be even. Why we can’t answer A?
I want to understand, if we know All the integer in S1 is even, and no matter y in s2 is odd or even, the x+y will be even. Why we can’t answer A?
