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Scott, Jean , and warren are all building wooden models for an archite

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Scott, Jean , and warren are all building wooden models for an archite  [#permalink]

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New post Updated on: 03 Jul 2019, 04:42
1
1
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

90% (01:35) correct 10% (00:49) wrong based on 21 sessions

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Scott, Jean , and warren are all building wooden models for an architectural presentation at noon tomorrow. If their individual probabilities of finishing on time are x, \(\frac{1}{3}\) , and \(\frac{1}{7}\) , respectively , then what is the probability that warren will finish on time but Jean and Scott will not ?



a. \(\frac{(21x-38)}{21}\)

b. \(\frac{12x}{21}\)

c. \(\frac{(2-2x)}{21}\)

d. \(\frac{(2-4x)}{21}\)

e. \(\frac{(4x-56)}{21}\)

Originally posted by CounterSniper on 30 Sep 2018, 00:41.
Last edited by SajjadAhmad on 03 Jul 2019, 04:42, edited 1 time in total.
Formatted Properly and added source.
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Re: Scott, Jean , and warren are all building wooden models for an archite  [#permalink]

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New post 30 Sep 2018, 00:52
1
All are independent activities.

The probability of finishing the task on time by individuals

Scott = x

Jean = 1/3

Warren = 1/7

The probability of not finishing the task on time.

Scott = 1-x

jean = 1-1/3 = 2/3

Warren = 1-1/7 = 6/7

Now,
Warren finishes on time, But Scott and Jean Don't.

the probability that Warren will finish on time but Jean and Scott will not = (1-x)*2/3*1/7 = \(\frac{(2-2x)}{21}\)

C is the answer.
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Re: Scott, Jean , and warren are all building wooden models for an archite   [#permalink] 30 Sep 2018, 00:52
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Scott, Jean , and warren are all building wooden models for an archite

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