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# Seed mixture X is 40 percent ryegrass and 60 percent

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Retired Moderator
Joined: 18 Jul 2008
Posts: 902
Seed mixture X is 40 percent ryegrass and 60 percent [#permalink]

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29 Oct 2008, 19:36
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Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?
(A) 10%
(B) 33.33 %
(C) 40%
(D) 50%
(E) 66.66 %

Anyone try the plug in number method for this one?

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Director
Joined: 14 Aug 2007
Posts: 695

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29 Oct 2008, 20:01
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?
(A) 10%
(B) 33.33 %
(C) 40%
(D) 50%
(E) 66.66 %

Anyone try the plug in number method for this one?

2/5x + 1/4y = 3/10(x+y)
0.4x - 0.3x = 0.3y - 0.25y
0.1x = 0.05y
x = 1/2y
2x = y

so (x+y) = 3x
x/3x = 1/3 = 0.3333 = 33.33%
Director
Joined: 23 May 2008
Posts: 743

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29 Oct 2008, 21:00
its always easier for me to use a chart....
Attachments

Book2.xls [13.5 KiB]

Retired Moderator
Joined: 18 Jul 2008
Posts: 902

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30 Oct 2008, 06:24
Yup, that's why I did as well. But then I tried to plug in numbers insteds for x and y, but couldn't get anything to resemble 33%

bigtreezl wrote:
its always easier for me to use a chart....
Retired Moderator
Joined: 18 Jul 2008
Posts: 902

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03 Nov 2008, 08:39
^bump. Anyone try pluggin in numbers?
Current Student
Joined: 28 Dec 2004
Posts: 3292
Location: New York City
Schools: Wharton'11 HBS'12

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03 Nov 2008, 08:49
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?
(A) 10%
(B) 33.33 %
(C) 40%
(D) 50%
(E) 66.66 %
Anyone try the plug in number method for this one?

.4X+0.25y=0.3(x+y)
0.1x=0.05y
x=0.05/0.1 or x=0.5y, then 0.5/1.5 or 5/15 *100 or 33.33%
Manager
Joined: 12 Oct 2008
Posts: 100

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03 Nov 2008, 09:09
^bump. Anyone try pluggin in numbers?

there's no need for that.

amount of weaker mix*(new mix-weaker mix)=amount of stronger mix *(stronger mix-new mix)
y*(30-25)=x*(40-10)
5y=10x
y=2x

So, if total weight is 300, x is 100, which is 1/3, or 33.33%

there's no need to plug in no's, or even use decimals (I always mess up adding or multiplying them ) It's all about proportions

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: PS: Seed Mixture   [#permalink] 03 Nov 2008, 09:09
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