TheRob wrote:

I tried to applied the following method

4 firstterm

8 second

16 third

32 fourth

64 fifth

...8 sixth

...6 seventh

...2 eighth

...4 ninth

...8 Tenth

I think you are going in the right direction. Last digit of 1st 4 numbers would be 4 (try 4*8*16*32).

Similarly, for product of each subsequent set of 4 numbers, last digit would be 4.

So, this means we have to find last digit of

..4*..4*..4.....(19 times)* ..4 * ..8 *...6

Now, for each 4*4*4, last digit would be 4

This reduces to

..4*..4*..4...(6 times) *4 *..4 * ..8 *...6

=(..4*..4) *..4 *..4 * ..8 *...6

=..4*..4 * ..8 *...6

=..8

So, last digit should be 8, answer A
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