|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
16 Jan 2019, 17:32
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
56% (02:07) correct
44%
(01:44)
wrong
based on 363
sessions
History
Date
Time
Result
Not Attempted Yet
Set A = {2, 3, 4, 5}, and set B = {4, 5, 6, 7, 8}. If P = the product of one number chosen from set A and one number chosen from set B, how many DIFFERENT values of P are possible?
A) 14
B) 15
C) 16
D) 18
E) 20
A) 14
B) 15
C) 16
D) 18
E) 20
Updated on: 14 Feb 2019, 04:24
Originally posted by MahmoudFawzy on 16 Jan 2019, 18:35.
Last edited by MahmoudFawzy on 14 Feb 2019, 04:24, edited 1 time in total.
Last edited by MahmoudFawzy on 14 Feb 2019, 04:24, edited 1 time in total.
Kudos
Bookmarks
IMO, D (16)
I solved it by multiplying each 2 numbers from different sets and excluding repeated products:
2|| 8,10,12,14,16
3||12,15,18,21,24
4||16,20,24,28,32
5||20,25,30,35,40
but is there a faster way?
I solved it by multiplying each 2 numbers from different sets and excluding repeated products:
2|| 8,10,12,14,16
3||
4||
5||
but is there a faster way?
17 Jan 2019, 12:05
Kudos
Bookmarks
Mahmoudfawzy83
Nice work - kudos to you!!
I don't believe there's a faster solution. In fact, I created the question to highlight the fact that, when it comes to counting questions, many students are reluctant to simply list and count the possible outcomes.
In this case, all 5 answer choices are relatively small, so we can be sure that it won't take long to list and count the outcomes.
That said, even when the answer choices are large, listing possible outcomes can often lead to useful insights regarding the correct answer.
I talk about all of this (and more) in the following video:
) 
