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Set Q contains p numbers, where p > 1. What is the ratio of the averag

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Joined: 02 Sep 2009
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Set Q contains p numbers, where p > 1. What is the ratio of the averag  [#permalink]

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New post 31 Jan 2017, 10:23
2
3
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

61% (01:18) correct 39% (01:22) wrong based on 85 sessions

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Senior Manager
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Joined: 24 Apr 2016
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Re: Set Q contains p numbers, where p > 1. What is the ratio of the averag  [#permalink]

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New post 09 Feb 2017, 15:41
1
Statement 1

For an evenly spaced set, Median = Mean.

Therefore ratio will be 1. Statement 1 is sufficient.

Statement 2

Since we do not have any information on the numbers, this statement is not sufficient.

Therefore answer is A
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Re: Set Q contains p numbers, where p > 1. What is the ratio of the averag  [#permalink]

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New post 10 Feb 2017, 00:27
1
Bunuel wrote:
Set Q contains p numbers, where p > 1. What is the ratio of the average of set Q to the median of set Q.

(1) Set Q is a set of consecutive even integers.
(2) p = 6


(1) - Set Q is a set of consecutive even integers.

Though for other sets the median=mean, I choose this set for condition A. {-2,0,2}. For this set mean=0 and median=0 hence mean/median= undefined. So I choose C.

Am I overthinking here?

Cheers!
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Re: Set Q contains p numbers, where p > 1. What is the ratio of the averag  [#permalink]

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New post 18 Oct 2018, 00:13
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Re: Set Q contains p numbers, where p > 1. What is the ratio of the averag   [#permalink] 18 Oct 2018, 00:13
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