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# Set S contains exactly 10 numbers and has an average (arithmetic mean)

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Math Expert
Joined: 02 Sep 2009
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Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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29 Mar 2016, 03:24
00:00

Difficulty:

5% (low)

Question Stats:

92% (00:53) correct 8% (01:25) wrong based on 92 sessions

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Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 5, while all other numbers remain the same, what is the new average of Set S?

A. 6.6
B. 6.7
C. 6.8
D. 6.85
E. 6.9

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Posts: 223
Re: Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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29 Mar 2016, 03:53
1
Old set S - Total is avg * no of elements = 6.2*10 = 62
If one number is increased by 5 then total increased to 62+5=67
New avg - 67/10 = 6.7.

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Re: Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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30 Mar 2016, 05:25
Sum => 62
here one value is increased by 5 => new sum = 67 so mean = 6.7
hence B
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Re: Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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08 Jan 2018, 09:15
Bunuel wrote:
Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 5, while all other numbers remain the same, what is the new average of Set S?

A. 6.6
B. 6.7
C. 6.8
D. 6.85
E. 6.9

Current Total = 62
After Increase by 5 total score is = 67

So, Average becomes 6.70

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Re: Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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08 Jan 2018, 09:35
Bunuel wrote:
Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 5, while all other numbers remain the same, what is the new average of Set S?

A. 6.6
B. 6.7
C. 6.8
D. 6.85
E. 6.9

Set S = (x + x + 1 + x + 2 .........., x + 10)/10 = 6.2

10x + 45 = 62

10x = 17

x = 1.7

Adding 5 in "x" we get new average as 1.7 + 5 = 6.7 (B)
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Re: Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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08 Jan 2018, 22:10
S = Sum of all numbers in the set
S/10 = 6.2
S = 62
Since the problem says one of the numbers in the set increases by 5, the sum of all the numbers also increases by 5.
Thus, S + 5 = 62 + 5
S + 5 = 67

If the new sum is 67, then the new average of the 10 numbers is 6.7 (Option B)
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Joined: 08 Dec 2017
Posts: 15
Set S contains exactly 10 numbers and has an average (arithmetic mean)  [#permalink]

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08 Jan 2018, 22:40
One number becomes increased by 5. So let's assume every number is 6.2
5 has to be distributed among 10 so each gets .5 more. 6.2+.5=6.7

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Set S contains exactly 10 numbers and has an average (arithmetic mean)   [#permalink] 08 Jan 2018, 22:40
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