Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
27 May 2018, 10:27
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
54% (02:32) correct
46%
(02:38)
wrong
based on 137
sessions
History
Date
Time
Result
Not Attempted Yet
Set S has a range of p and the largest number in set S is v. Set T has a range of q and the largest number in set T and the largest number in set T is w. Is the smallest number in set S greater than the smallest number in set T?
(1) p < q
(2) The median of set S is less than the median of set T, and the average (arithmetic mean) of set S is greater than the mean of set T.
(1) p < q
(2) The median of set S is less than the median of set T, and the average (arithmetic mean) of set S is greater than the mean of set T.
27 Jun 2018, 06:40
Kudos
Bookmarks
As per question
Set S
Smallest in set S=v-p
Set T
Smallest in T=w-q
(1) p < q
No info about v and w
So insufficient
(2) The median of set S is less than the median of set T, and the average (arithmetic mean) of set S is greater than the mean of set T.
We don't know how many numbers are there in each set S and T
As this thing would result in situation where either of s or T can be greater than other
Insufficient
Combining also won't give anything
So answer is E
Give kudos if it helps
Posted from my mobile device
Set S
Smallest in set S=v-p
Set T
Smallest in T=w-q
(1) p < q
No info about v and w
So insufficient
(2) The median of set S is less than the median of set T, and the average (arithmetic mean) of set S is greater than the mean of set T.
We don't know how many numbers are there in each set S and T
As this thing would result in situation where either of s or T can be greater than other
Insufficient
Combining also won't give anything
So answer is E
Give kudos if it helps
Posted from my mobile device
15 Sep 2025, 11:38
Kudos
Bookmarks
Bunuel
Neither statement nor both statements together are sufficient to determine if the smallest number in set S is greater than the smallest number in set T, because the provided information about the range and the relative values of medians and means is insufficient to make this comparison. For example, even with the conditions in statement (2) met, we can construct scenarios where the smallest number in S is larger or smaller than the smallest in T.
Why Statement (1) is not sufficient:
p < q (the range of set S is less than the range of set T).
Knowing that S has a smaller range than T, along with the specific largest numbers (v for S and w for T), does not tell us about their respective smallest numbers. It's possible for S to have a smaller range but still contain a large smallest number.
Why Statement (2) is not sufficient:
The median of set S is less than the median of set T, and the average (arithmetic mean) of set S is greater than the mean of set T.
While this statement provides information about the central tendency and distribution of the sets, it's still not enough to definitively compare the smallest elements. You can have sets with different medians and means where the smallest value in the set with the higher mean is still larger or smaller than the smallest value in the set with the lower mean.
Why Statements (1) and (2) together are not sufficient:
Even when combining both conditions, we still cannot find a definitive answer. We would need more information about the number of elements in each set or how those elements are distributed relative to their known ranges and central tendencies.
Source: AI Overview
