Tan2017
Set S of Cardinality of 7 has distinct elements. Is the probability of picking out a prime number from Set S less than 4/5?
(1)The least element and the largest element of Set S are 8 and 18 respectively
(2) If 2 prime elements are added into Set S, the probability that a prime number is picked up from the extended set S is 1/3
Cardinality 7 => the set has 7 elements (distinct).
A) least element is 8, largest is 18. So there are remaining 5 other elements. Maximum number of prime numbers possible between 8 and 18 is 3: 11, 13, 17. The maximum possible probability of picking a prime number from 7 numbers between 8 and 18 => 3/7 (Assuming all prime numbers between 8 and 18 are part of set S). 3/7 < 4/5 . Since the maximum possible probability is already less, we can answer YES to the question. Hence A is sufficient.
B) Lets say we have n prime numbers in the set. The initial probability will be n/7. Now we add two additional prime numbers to the set making it (n+2) prime numbers in a set of 9 elements. So new probability = (n+2)/9 . This new probability is given as equal to 1/3.
(n+2)/9 = 1/3 => n=1 => This means there is only 1 prime number in the set of 7 elements.
So initial probability: 1/7. Which is definitely less than 4/5. Answers YES to the asked question. Hence B is sufficient.
So answer (D) each statement individually is sufficient.