|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (01:51) correct
39%
(01:48)
wrong
based on 342
sessions
History
Date
Time
Result
Not Attempted Yet
Set X consists of ten consecutive integers. Set Y consists of all the distinct integers that result from adding 2 to each of the integers in set X and all the integers that result from subtracting 2 from each of the integers in set X. How many more integers are there in set Y than in set X ?
A. 0
B. 4
C. 10
D. 14
E. 20
A. 0
B. 4
C. 10
D. 14
E. 20
10 Apr 2021, 17:05
Kudos
Bookmarks
Solution:
SetX: x , x+1, x+2, x+3, x+4, x+5,+x+6 ,x+7, x+8,x+9
Total 10
Set y:
x+2, x+3, x+4, x+5,+x+6 ,x+7, x+8,x+9, x+10, x+11
and
x-2 , x-1, x , x+1,x+2, x+3, x+4, x+5,+x+6 ,x+7
Y becomes: x-2 , x-1, x , x+1,x+2, x+3, x+4, x+5,x+6 ,x+7, x+8,x+9, x+10, x+11
Total 14
Alternatively, say X= 1,2,3,4,5,6,7,8,9,10 = 10 elements
Y becomes =
3,4,5,6,7,8,9,10,11,12
And ,-1,0 , 1,2,3,4,5,6,7,8
-1,0,1,2,3,4,5,6,7,8,9,10,11,12= 14 elements
Hence 4
SetX: x , x+1, x+2, x+3, x+4, x+5,+x+6 ,x+7, x+8,x+9
Total 10
Set y:
x+2, x+3, x+4, x+5,+x+6 ,x+7, x+8,x+9, x+10, x+11
and
x-2 , x-1, x , x+1,x+2, x+3, x+4, x+5,+x+6 ,x+7
Y becomes: x-2 , x-1, x , x+1,x+2, x+3, x+4, x+5,x+6 ,x+7, x+8,x+9, x+10, x+11
Total 14
Alternatively, say X= 1,2,3,4,5,6,7,8,9,10 = 10 elements
Y becomes =
3,4,5,6,7,8,9,10,11,12
And ,-1,0 , 1,2,3,4,5,6,7,8
-1,0,1,2,3,4,5,6,7,8,9,10,11,12= 14 elements
Hence 4
12 Apr 2021, 16:12
Kudos
Bookmarks
mSKR
Not sure I agree with this - the question stem does not ask for elements in each set, only integers. Further, it specifically states that Y consists of ALL integers that are +, - X values.
Therefore, even if Y has more than one of the same integer, I believe the instruction is such that we count it. Y is therefore higher (I think ~20 integers give or take?)
