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18 Sep 2019, 08:25
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E
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Seven times a two digit number is equal to four times the number obtained by reversing its digits. How many such different numbers are possible?
(A) None
(B) 1
(C) 2
(D) 3
(E) 4
(A) None
(B) 1
(C) 2
(D) 3
(E) 4
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18 Sep 2019, 08:39
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Nidasamad
Seven times a two digit number is equal to four times the number obtained
by reversing its digits. How many such different numbers are possible?
(A) None
(B) 1
(C) 2
(D) 3
(E) 4
by reversing its digits. How many such different numbers are possible?
(A) None
(B) 1
(C) 2
(D) 3
(E) 4
Let the 2 digit number = xy
Value = 10x + y
The number when reversed = yx
Value = 10y + x
Given, 7(10x + y) = 4(10y + x)
—> 70x + 7y = 40y + 4x
—> 66x = 33y
—> 2x = y
So, units digit is twice the tens digit
—> Possible Values = 12, 24, 36, 48
Option E
Posted from my mobile device
18 Sep 2019, 08:40
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Numbers: ab & ba
7(10a+b)=4(10b+a)
66a=33b
b=2a
If a:{1,2,3,4}
b would be{2,4,6,8}
So, We have four such numbers.
12,24,36,48
Option E
Posted from my mobile device
7(10a+b)=4(10b+a)
66a=33b
b=2a
If a:{1,2,3,4}
b would be{2,4,6,8}
So, We have four such numbers.
12,24,36,48
Option E
Posted from my mobile device
