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Hello all, I have a question regarding arithmetic, which seems simple enough but when I come across this step in a problem I cannot say that I recognize the need for it. I will give you an example.
Solve the following for d:
y(t-d/x)=d/2
2xy(t-d/2x)=dx*
2xyt-dy=dx 2xyt=dx+dy 2xyt=d(x+y) (2xyt)/(x+y)=d
The boldface equation represents my problem, namely the step when one multiplies both sides by dx, specifically the variable x. I am having trouble with the logic of doing this and have come to the conclusion that this is done in order to cancel out the x in (d/2x). Is this correct?
Thanks in advance!
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If I am reading this equation correctly, then this is how you would approach it:
y(t-d)/x=d/2
Multiply both sides by 2, in order to get 2y(t-d)/x=d Multiply both sides by x, in order to get 2y(t-d)=dx Distribute, in order to get 2yt-2yd=dx Move the term with d to right, to get 2yt=dx+2yd Factor out the d, to get 2yt=d(x+2y) Divide by x+2y, to isolate d and get d=2yt/(x+2y)
If you struggle with the multipying by the denominator portion, I would recommend doing them one at a time. So rather than multiplying through by 2x, multiply by 2 first, and then x in the next step.
I hope this helps!!!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.