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Bunuel
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Could you please clarify my doubt and let me know where I might be going wrong?

Since it’s stated that two marbles are being drawn consecutively, shouldn’t the probability be calculated as:

(30/75) * (29/74)?

Initially, there are 30 white marbles. After drawing one, 29 remain, leading to this conclusion.

I’m basing this approach on similar probability questions of the similar type.


chetan2u
Bunuel
Two marbles are drawn in succession from a box containing 10 red, 30 white, 20 blue, and 15 orange marbles, replacement being made after each drawing. What is the probability that both are white?

(A) 11/15
(B) 16/25
(C) 64/225
(D) 4/25
(E) 4/75


Total marbles : 10+30+20+15=75

1) Both white
P of W-W = \(\frac{30}{75}*\frac{30}{75}=\frac{4}{25}\)

D
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Could you please clarify my doubt and let me know where I might be going wrong?

Since it’s stated that two marbles are being drawn consecutively, shouldn’t the probability be calculated as:

(30/75) * (29/74)?

Initially, there are 30 white marbles. After drawing one, 29 remain, leading to this conclusion.

I’m basing this approach on similar probability questions of the similar type.


chetan2u
Bunuel
Two marbles are drawn in succession from a box containing 10 red, 30 white, 20 blue, and 15 orange marbles, replacement being made after each drawing. What is the probability that both are white?

(A) 11/15
(B) 16/25
(C) 64/225
(D) 4/25
(E) 4/75


Total marbles : 10+30+20+15=75

1) Both white
P of W-W = \(\frac{30}{75}*\frac{30}{75}=\frac{4}{25}\)

D


You are missing the highlighted part in the stem: ...replacement being made after each drawing. This means that when a marble is drawn, it is put back, so the second draw is again from 75 total marbles, not 74. Similarly, if a white ball is drawn, it is put back, so for the second draw, we still have the initial number of white balls: 30.

Hope it's clear.
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