Six movie critics each gave the lastest Dan Smuthers film an integer score from 0-100. The mode and median of these scores was 82 and the range of scores was 50. How many possiblilities are there for the second lowest score if the mean of the six scores is 78 and the highest score is 99?
MEDIAN = MODE = 82 MEAN THAT AT LEAST THE MIDDLE TWO CRITICS GAVE 82......(IE IT EXISTS AS A VALUE)
RANGE DIFFERENCE BETWEEN THE EXTREEMS = 50
MEAN = 78 SUM = 78*6 = 468 - 164 = 304 REAMINING FOUR VALUES
IF HIGHEST SCORE IS 99 THUS THE REMAINING THREE = 205
LOWEST SCORE = 49
THE REMAINING TWO = 205 - 49= 156
THE SECONF LOWEST HAS TO BE > 44 AND THE REMAINING ONE IS LESS THAN 99 ( NOT EQUALL BECAUSE IF EQUAL 82 WONT BE THE MODE or more so it wont be the max value)
THUS IT COULD BE
156 - 99 = 57 < X ( OUR VALUE)
IF WE ASSUMED THAT THERE IS THREE 82 VALUES THEN WE CAN ASSUME THAT IT COULD BE EQUIVELANT TO 99
82*3 + 99*2 + 49= 493 BUT SUM IS 468 ....NOT A VALID ASSUMBTION
I BELIEVE IT CAN TAKE VALUE 58<=X<82 ( ie maximizing the third lowest to be 98)
total possibilities = 81 - 58+1 = 24
edited for wrong addition and subtraction