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25 Aug 2016, 14:57
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Hi All,
I had a question with respect to the slopes of perpendicular lines. This is a very basic question but i am slightly puzzled because I cant seem to reason it out.
The generally known formula is that if we have two lines L1 and L2 which are perpendicular and have the the slopes M1 and M2 respectively then "M1*M2= -1".
Now, lets say L1 is parallel to Y axis ( they have the same X coordinates) and L2 is parallel to X axis ( they have the same Y coordinate).These two lines intersect at point P. The formula to find the slope of a line is \(\frac{y2-y1}{x2-x1}\)
In this case, x2-x1 for L1 will be 0 and thus the slope will be undefined. However the slope M2 will be 0.
How do we apply the M1*M2 rule here as it will be ( undefined * 0). I want to understand what am i missing in this basic concept.
Regards,
Shradha
I had a question with respect to the slopes of perpendicular lines. This is a very basic question but i am slightly puzzled because I cant seem to reason it out.
The generally known formula is that if we have two lines L1 and L2 which are perpendicular and have the the slopes M1 and M2 respectively then "M1*M2= -1".
Now, lets say L1 is parallel to Y axis ( they have the same X coordinates) and L2 is parallel to X axis ( they have the same Y coordinate).These two lines intersect at point P. The formula to find the slope of a line is \(\frac{y2-y1}{x2-x1}\)
In this case, x2-x1 for L1 will be 0 and thus the slope will be undefined. However the slope M2 will be 0.
How do we apply the M1*M2 rule here as it will be ( undefined * 0). I want to understand what am i missing in this basic concept.
Regards,
Shradha
Senthil1981
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25 Aug 2016, 16:15
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Hi Shrada,
What you've described is actually the X-Y plane moved . And slope of line parallel to X axis is tan 0 and other is tan 90, which is undefined. And between these any two perpendicular lines will have slope multiplied as -1. Also slope of a line is measured with reference to X and Y axis.
What you've described is actually the X-Y plane moved . And slope of line parallel to X axis is tan 0 and other is tan 90, which is undefined. And between these any two perpendicular lines will have slope multiplied as -1. Also slope of a line is measured with reference to X and Y axis.
25 Aug 2016, 16:31
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Senthil1981
Hi Shrada,
What you've described is actually the X-Y plane moved . And slope of line parallel to X axis is tan 0 and other is tan 90, which is undefined. And between these any two perpendicular lines will have slope multiplied as -1. Also slope of a line is measured with reference to X and Y axis.
What you've described is actually the X-Y plane moved . And slope of line parallel to X axis is tan 0 and other is tan 90, which is undefined. And between these any two perpendicular lines will have slope multiplied as -1. Also slope of a line is measured with reference to X and Y axis.
Hi Senthil,
I am still unclear. I still dont get how the the slope of these two lines that i mentioned ( undefined and 0) when multiplied give a product equivalent to -1.
Regards,
Shradha
