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12 Dec 2024, 13:51
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\(S_{n} = 2n - 5\) for all integers n ≥ 1. What is the 11th term of the sequence?
31 Dec 2024, 02:13
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\(S_{n} = 2n - 5\)
To find the 11th term we will replace n with 11 in \(S_{n} = 2n - 5\)
=> \(S_{11} = 2*11 - 5\) = 22 - 5 = 17
So, Answer will be 17
Hope it helps!
Watch the following video to MASTER Sequences
To find the 11th term we will replace n with 11 in \(S_{n} = 2n - 5\)
=> \(S_{11} = 2*11 - 5\) = 22 - 5 = 17
So, Answer will be 17
Hope it helps!
Watch the following video to MASTER Sequences
31 Dec 2024, 02:23
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I have 1 doubt like they are asking for the 11th term you find the sum of 11 terms ..
It may be goes like :
11th term = S10-S11
So S10 = 2*10-5=15
S11 = 2*11-5 =17
So 11th term would be 2
It may be goes like :
11th term = S10-S11
So S10 = 2*10-5=15
S11 = 2*11-5 =17
So 11th term would be 2
