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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
ArvindCrackVerbal wrote:
Assuming simple values is probably the fastest and the best method in solving this question.

Let’s assume that Sofia used to deliver 100 boxes a month before the workflow manager was hired. Let’s also say that she worked a total of 10 hours to do this work. Her productivity would then be 10 boxes per hour.

Once the workflow manager was hired, Sofia delivered 20 percent more boxes. This means that she’s now able to deliver 120 boxes. At the same time, she worked 20 percent fewer hours to get this work done which means she worked a total of 8 hours. Her productivity would now be 15 boxes per hour (120 boxes/8 hours).

From 10 boxes/hour to 15 boxes/hour, we see that the increase in Sofia's productivity is 50%. The correct answer option is B.

Hope that helps!


hi...i chose 40 hr per week...and didnt get the answer....can you look at my solution and tell me where i went wrong?
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
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Mansoor50 wrote:
ArvindCrackVerbal wrote:
Assuming simple values is probably the fastest and the best method in solving this question.

Let’s assume that Sofia used to deliver 100 boxes a month before the workflow manager was hired. Let’s also say that she worked a total of 10 hours to do this work. Her productivity would then be 10 boxes per hour.

Once the workflow manager was hired, Sofia delivered 20 percent more boxes. This means that she’s now able to deliver 120 boxes. At the same time, she worked 20 percent fewer hours to get this work done which means she worked a total of 8 hours. Her productivity would now be 15 boxes per hour (120 boxes/8 hours).

From 10 boxes/hour to 15 boxes/hour, we see that the increase in Sofia's productivity is 50%. The correct answer option is B.

Hope that helps!


hi...i chose 40 hr per week...and didnt get the answer....can you look at my solution and tell me where i went wrong?



Hello Mansoor,

You have brought in too many values while trying to solve the question. The problem with this is that more variables means more things to keep a tab on. When you have to handle more variables under a time constraint, it's very natural to miss some of them out.

That's exactly what has happened here. You have just found the difference between the two different cases of productivity. But, you have forgotten to compare it with the initial value and that is where the slip up has happened.

Remember, Percentage Increase = \(\frac{Final Value - Initial Value }{ Initial Value}\) * 100.

You did find out the numerator, but forgot to compare it with the denominator and simplify. Also, you did not simplify 100/160 to 5/8 and 120/128 to 15/16; instead you kept using the same values to find the difference. Under a time constraint, when you feed your brain with bigger numbers, many times it gets overwhelmed and that's when the calculation mistakes crop up. So, remember to simplify fractions to their lowest form as much as you can.

So, here's what you SHOULD HAVE done:

Percentage Increase = (15/16) - (5/8) / (5/8) * 100 = (5/16) / (5/8) * 100 = 1/2 * 100 = 50%.

You faltered at the final step, hard luck! But hey, it was just a minor detail that you overlooked, so it's okay. Your reasoning wasn't faulty.

Hope that helps!
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
ArvindCrackVerbal wrote:
Mansoor50 wrote:
ArvindCrackVerbal wrote:
Assuming simple values is probably the fastest and the best method in solving this question.

Let’s assume that Sofia used to deliver 100 boxes a month before the workflow manager was hired. Let’s also say that she worked a total of 10 hours to do this work. Her productivity would then be 10 boxes per hour.

Once the workflow manager was hired, Sofia delivered 20 percent more boxes. This means that she’s now able to deliver 120 boxes. At the same time, she worked 20 percent fewer hours to get this work done which means she worked a total of 8 hours. Her productivity would now be 15 boxes per hour (120 boxes/8 hours).

From 10 boxes/hour to 15 boxes/hour, we see that the increase in Sofia's productivity is 50%. The correct answer option is B.

Hope that helps!


hi...i chose 40 hr per week...and didnt get the answer....can you look at my solution and tell me where i went wrong?



Hello Mansoor,

You have brought in too many values while trying to solve the question. The problem with this is that more variables means more things to keep a tab on. When you have to handle more variables under a time constraint, it's very natural to miss some of them out.

That's exactly what has happened here. You have just found the difference between the two different cases of productivity. But, you have forgotten to compare it with the initial value and that is where the slip up has happened.

Remember, Percentage Increase = \(\frac{Final Value - Initial Value }{ Initial Value}\) * 100.

You did find out the numerator, but forgot to compare it with the denominator and simplify. Also, you did not simplify 100/160 to 5/8 and 120/128 to 15/16; instead you kept using the same values to find the difference. Under a time constraint, when you feed your brain with bigger numbers, many times it gets overwhelmed and that's when the calculation mistakes crop up. So, remember to simplify fractions to their lowest form as much as you can.

So, here's what you SHOULD HAVE done:

Percentage Increase = (15/16) - (5/8) / (5/8) * 100 = (5/16) / (5/8) * 100 = 1/2 * 100 = 50%.

You faltered at the final step, hard luck! But hey, it was just a minor detail that you overlooked, so it's okay. Your reasoning wasn't faulty.

Hope that helps!


a big thank you!!
its good to know my thought process was correct...means a lot
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
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The way I approached this questions is mentioned below:
Productivity = Total number of boxes delivered per unit time.
so, P1 = n/x
P2 = 1.2n/0.8x
Increase in Productivity = (P2-P1)/P1 = 50%
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
Assumptions:

earlier: 100 boxes in 100 hours. Productivity =1
Now : 120 boxes in 80 hours. Productivity = 1.5
Change in productivity = 1.5-1 = 0.5
% change = (0.5/1) * 100 = 50%
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
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Re: Sofia runs a business delivering boxes of frequently used household su [#permalink]
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