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18 Sep 2022, 18:52
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Hi my friends,
To clarify you can only solve linear equations by combinations if you are looking for what x+y equal to? If you were looking for just x or just y, you should use elimination or substitution.
For example, if I wanted to find x+y from the following two equations... I would use a combination:
2x+y=18
+ x+2y=12
= 3x+3y=30
= x+y=10
But, if I wanted to solve for just x and y individually, I would need to use elimination or substitution?
To clarify you can only solve linear equations by combinations if you are looking for what x+y equal to? If you were looking for just x or just y, you should use elimination or substitution.
For example, if I wanted to find x+y from the following two equations... I would use a combination:
2x+y=18
+ x+2y=12
= 3x+3y=30
= x+y=10
But, if I wanted to solve for just x and y individually, I would need to use elimination or substitution?
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21 Sep 2022, 20:08
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woohoo921
The moment you want individual values, you have to ensure that one of the variables is cancelled by some means. The means are substitution, elimination etc.
Also, it is not that moment you look at x+y, combining two equations is the way ahead.
Say equations are 2x+y=18 and 2x+2y=20.
Here, the better way would be to subtract first from second to get value of y and then work for x.
And when you get x and y, x+y is not a tough ask.
However, the questions dealing with value of x+y in DS questions would require extra caution.
For example, if \(x^2+2y^2+xy=y^2-xy\) in a statement and you are asked value of x+y
This will simplify into \((x+y)^2=0\), so x+y=0.
Thus, you do nothing require another statement here.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
