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Amit05
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Some problems ... roller coaster and inequality 15 Sep 2007, 23:54
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Please suggest the solution .



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Some problems ... roller coaster and inequality 16 Sep 2007, 00:08
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first - Roller coaster:

total = 9
all three = 1
so prob = 1/9
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Some problems ... roller coaster and inequality 16 Sep 2007, 00:12
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Second: E.

1: 2x > y.
2: y > x.

from 1 and 2: 2x > y > x. so insufficient..
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Some problems ... roller coaster and inequality 16 Sep 2007, 00:41
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Fistail
first - Roller coaster:

total = 9
all three = 1
so prob = 1/9
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You are wrong.. or OA is wrong.. which one do you think ?
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Amit05
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Some problems ... roller coaster and inequality 16 Sep 2007, 00:43
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Fistail
Second: E.

1: 2x > y.
2: y > x.

from 1 and 2: 2x > y > x. so insufficient..
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Yes, you are right.. The OA is E. Even I had got it right.. I don;t know why I posted this question ..:)
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Some problems ... roller coaster and inequality 16 Sep 2007, 02:27
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Roller Coaster
Probab = 3/3*2/3*1/3 =2/9
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Some problems ... roller coaster and inequality 16 Sep 2007, 02:27
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For the DS, none of the st. are suff. so E
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Some problems ... roller coaster and inequality 16 Sep 2007, 03:08
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Artemov
Roller Coaster
Probab = 3/3*2/3*1/3 =2/9
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Could you please explain your reasoning ..??
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Some problems ... roller coaster and inequality 16 Sep 2007, 07:55
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Fistail
first - Roller coaster:

total = 9
all three = 1
so prob = 1/9
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total = 3^3 = 27
all three = 3! = 6
so prob = 6/27 = 2/9
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defenestrate
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Some problems ... roller coaster and inequality 16 Sep 2007, 20:27
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Amit05
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Roller Coaster
Probab = 3/3*2/3*1/3 =2/9

Could you please explain your reasoning ..??
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when he first steps up to ride it does not matter which car he takes since he only has to ride in each car once so 3/3

second time round it does there are only 2/3 cars he can ride in and the third time he must ride in the last car 1/3

so 2/3*1/3=2/9 (of course one could argue that he could increase his chances by bribing the people placing passengers on the rids)
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Some problems ... roller coaster and inequality 16 Sep 2007, 22:40
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P(first car) = P(second car) = P(third car) = 1/3

If the cars are A,B and C and the passenger can sit in any orders, then there are 6 ways to permute how the passenger sits in the cars. Each way = 1/27. So 6 ways = 6/27 = 2/9
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Some problems ... roller coaster and inequality 16 Sep 2007, 22:45
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St1:

2x > y
4x > 2y.

St1 is insufficient as 4x could be greater than 3y, or less than 3y.

St2:
x < y
4x < 4y.
Insufficient. 4x could be greater than 3y or less than 3y.

St1 & St2:
2y < 4x < 4y
Insufficient. COuld be greater than 3y or less than 3y.

Ans E



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