sorry if this was recently discussed - i tried to look but

Question

sorry if this was recently discussed - i tried to look but couldn't find it.

 Is x>1?

1). x^2<x

2). x<rootx

Rayn · Answer

I had D.

Both statements are the same.

Now, if x^2<x
then x is between 0 and 1.

AK47 · Answer

x<root x
implies x^2 < x
 x(x-1)<0
hence 0<x<1

hence x cant be greater than 1

choice b as per me.

what's the OA????

kripalkavi · Answer

X^2 < X is the same as the first statement!! It has to be D.

yezz · Answer

Is x>1? 

1). x^2<x 

2). x<rootx

from one 

x^2 < x then x is positive and a fraction.......suff


from two

x<sqrt x ie x is a =ve fraction....suff

my answer is D

yogeshsheth · Answer

My ANswer
St 1 says 
x^2<x ...x^2-x<0...0<x<1...thus sufficient

St2

x<x^(1/2)..x<x^2 which is same as st1

My answer is D

anandsebastin · Answer

Should be  D 

Statement 1: 
x^2 <1 only when x<1 SUFF

Statement 2:
x<sqrt(x) only when x<1 SUFF

sorry if this was recently discussed - i tried to look but

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