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# Square root ?? Doubt

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Intern
Joined: 06 Apr 2011
Posts: 18
Square root ?? Doubt [#permalink]

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29 Jul 2012, 06:52
If Sqrt(x) is an Integer.can x be Non integer ??
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Joined: 02 Sep 2009
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Re: Square root ?? Doubt [#permalink]

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29 Jul 2012, 07:07
riteshv wrote:
If Sqrt(x) is an Integer.can x be Non integer ??

The answer is NO.

Given: $$\sqrt{x}=integer$$ --> square this equation: $$x=integer^2$$. Now, since $$integer^2$$ is always an integer then $$x=integer^2=integer$$. So, $$\sqrt{x}=integer$$ means that $$x$$ must be an integer.

P.S. Please post general math questions in General Math forum.
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Joined: 25 Jun 2012
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Re: Square root ?? Doubt [#permalink]

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30 Jul 2012, 17:07
Simply put - an integer multiplied by another integer will always give you an integer. If you want to get something that's not an integer, you're going to have to add a factor that's not an integer - something that is a fraction, or is irrational, and such.

Therefore, if rt(x) is an integer, then x is an integer.
Re: Square root ?? Doubt   [#permalink] 30 Jul 2012, 17:07
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# Square root ?? Doubt

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