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# Squares and Triples.

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Intern
Joined: 01 Dec 2009
Posts: 7

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28 Jun 2010, 08:58
If x^2 + y^2 = 169, Can I assume (x,y) = (5,12) or (12,5) If:
x>0, y>0 and (x,y) are integers?
Thanks.

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Manager
Joined: 16 Apr 2010
Posts: 212

Kudos [?]: 147 [0], given: 12

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28 Jun 2010, 11:18
Yes you can

Kudos [?]: 147 [0], given: 12

Intern
Joined: 21 Jun 2010
Posts: 3

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29 Jun 2010, 06:04
Another point of view .. ( just a thought )
Since they comply with the form
$$x^2 + y^2 = z^2$$
Just look at those values as pythagorean triplets.
eg : (5,12,13) (6,8,10) etc
So to have a hypotenuse of 13 ( which is $$\sqrt{169}$$ ) the only possible values of the other two sides are 12 and 5 ( given that they are integer values )

On that ... a doubt just popped into my mind .. .
Can we have non-integer values for pythagorean triplets ? Can anyone answer ?

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Manager
Joined: 26 Mar 2010
Posts: 116

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02 Jul 2010, 06:31
I have a doubt too!!!

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Intern
Joined: 21 Jun 2010
Posts: 3

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06 Jul 2010, 01:04
Yep ! Yep ! You are right. Thanks

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Re: Squares and Triples.   [#permalink] 06 Jul 2010, 01:04
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