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06 Dec 2020, 08:29
Kudos
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\(distance\) = \(rate\) * \(time\)
We can create the following equation:
\(27 = 1.25rt + rt\)
\(27 = 2.25rt\)
\(\frac{27}{2.25} = rt\)
\(12 = rt\)
Since the question asks for Stacy's rate, which is \(1.25rt\):
\(1.25rt = 15\)
Answer is C.
We can create the following equation:
\(27 = 1.25rt + rt\)
\(27 = 2.25rt\)
\(\frac{27}{2.25} = rt\)
\(12 = rt\)
Since the question asks for Stacy's rate, which is \(1.25rt\):
\(1.25rt = 15\)
Answer is C.
14 Dec 2020, 01:11
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They both leave at the Same time from Opposite directions walking towards each other. The Time each spends walking is Constant.
Over this Same Time, the Ratio of the Speeds at which the 2 girls walk will be Directly Proportional to the Ratio of the Distances the 2 girls each cover.
Stacy's Speed is 25% Greater than Katie's
A = B + (25%)B
A = B + (1/4)B
A = (5/4)B
A/5 = B/4
Ratio of Stacy's Speed - to - Katy's Speed = 5 : 4
thus, the Distance Stacy Covers - to - the Distance Katy Covers = 5 : 4
Stacy will cover (5) / (5 + 4) = 5/9th of the Distance between them when they meet.
27 miles is between them.
Stacy Covers -----> (5/9) * (27 miles) = 15 miles
-C-
Over this Same Time, the Ratio of the Speeds at which the 2 girls walk will be Directly Proportional to the Ratio of the Distances the 2 girls each cover.
Stacy's Speed is 25% Greater than Katie's
A = B + (25%)B
A = B + (1/4)B
A = (5/4)B
A/5 = B/4
Ratio of Stacy's Speed - to - Katy's Speed = 5 : 4
thus, the Distance Stacy Covers - to - the Distance Katy Covers = 5 : 4
Stacy will cover (5) / (5 + 4) = 5/9th of the Distance between them when they meet.
27 miles is between them.
Stacy Covers -----> (5/9) * (27 miles) = 15 miles
-C-
02 Aug 2025, 10:23
Kudos
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
