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nik256
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Subtraction 15 Nov 2022, 00:12
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When y-x = Z and z>x, what must be true for y?

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nik256
When y-x = Z and z>x, what must be true for y?
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With the information that you have provided there isn't much we can predict about y, except y = x + z (already mentioned in the question stem).

Can you provide more context around what you're looking for. A reference to a question will help.
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Subtraction 15 Nov 2022, 00:33
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nik256
When y-x = Z and z>x, what must be true for y?

With the information that you have provided there isn't much we can predict about y, except y = x + z (already mentioned in the question stem).

Can you provide more context around what you're looking for. A reference to a question will help.
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IS y (positive or negative)?
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Subtraction 15 Nov 2022, 00:41
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IS y (positive or negative)?
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I don't know :dontknow:

Depends the position of x and z with respect to 0 on the number line.

z = 5; x = -5 --> y = 0 (neither positive nor negative)

z = 6; x = -2 --> y = 4 (positive)

z = 6; x = 2 --> y = 8 (positive)

z = -6; x = -10 --> y = -16 (negative)

:)
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nik256

IS y (positive or negative)?

I don't know :dontknow:

Depends the position of x and z with respect to 0 on the number line.

z = 5; x = -5 --> y = 0 (neither positive nor negative)

z = 6; x = -2 --> y = 4 (positive)

z = 6; x = 2 --> y = 8 (positive)

z = -6; x = -10 --> y = -16 (negative)

:)
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ohh sorry,

it's x-y not y-x
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ohh sorry,

it's x-y not y-x
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No worries !

So the question essential is

When z = x - y and z > x, what is the (positive or negative) nature of y ?

We know that z lies to the right of x on the number line. So, z - x is positive.

y = x - z

As z - x is positive, x - z will be negative.

Hence y is negative.
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Subtraction 15 Nov 2022, 03:18
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gmatophobia


No worries !

So the question essential is

When z = x - y and z > x, what is the (positive or negative) nature of y ?

We know that z lies to the right of x on the number line. So, z - x is positive.

y = x - z


thank you

As z - x is positive, x - z will be negative.

Hence y is negative.
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