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Difficulty:
25%
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Question Stats:
80% (02:33) correct
20%
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wrong
based on 64
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Sue and Nancy wish to buy a snack. They combine their money and find they have $4.00, consisting of quarters, dimes, and nickels. If they have 35 coins and the number of quarters is half the number of nickels, how many quarters do they have?
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
25 Aug 2013, 06:00
Kudos
Bookmarks
Asifpirlo
Sue and Nancy wish to buy a snack. They combine their money and find they have $4.00, consisting of quarters, dimes, and nickels. If they have 35 coins and the number of quarters is half the number of nickels, how many quarters do they have?
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
q + d + n = 35;
The number of quarters is half the number of nickels --> n = 2q --> q + d + 2q = 35;
25q + 10d + 5n = 400 --> 25q + 10d + 5*2q = 400 --> 5q + 2d + 2q = 80.
Solving q + d + 2q = 35 and 5q + 2d + 2q = 80 gives q = 10.
Answer: B.
25 Aug 2013, 15:34
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Bunuel
Asifpirlo
Sue and Nancy wish to buy a snack. They combine their money and find they have $4.00, consisting of quarters, dimes, and nickels. If they have 35 coins and the number of quarters is half the number of nickels, how many quarters do they have?
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
(A) 5
(B) 10
(C) 20
(D) 3
(E) 6
q + d + n = 35;
The number of quarters is half the number of nickels --> n = 2q --> q + d + 2q = 35;
25q + 10d + 5n = 400 --> 25q + 10d + 5*2q = 400 --> 5q + 2d + 2q = 80.
Solving q + d + 2q = 35 and 5q + 2d + 2q = 80 gives q = 10.
Answer: B.
This is an easy problem but 25q + 10d + 5n = 400 is the equation i have to use quickly.
you used algebra but i often try with this sort problem via COUNTING method and i kill time by doing so...
