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Supermarket D uses 2 tracking systems, S-1 and S-2. Both tracking systems use codes, each of which is an ordered sequence of 6 characters. Each code for S-1 consists of 2 digits, each chosen from 0 through 9, followed by 4 letters, each chosen from A through Z but excluding vowels (A, E, I, O, U) and Y. Each code for S-2 consists of 4 digits, each chosen from 0 through 9, followed by 2 letters, each chosen from A through Z but excluding vowels and Y. What fraction of the possible number of S-1 codes is the possible number of S-2 codes? (Note: There are 20 letters from A through Z, excluding vowels and Y.)
Am sorry, no options, but will appreciate your contributions.
If the 1st tracking system uses different combinations (2D 4L), how can we have some common elements with
the 2nd tracking system, which uses (4D 2L)?
Am sorry, no options, but will appreciate your contributions.
If the 1st tracking system uses different combinations (2D 4L), how can we have some common elements with
the 2nd tracking system, which uses (4D 2L)?
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09 Nov 2012, 01:49
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gmatbull
Question is not asking for common elements and as you rightly mentioned there cant be common codes as one is 2D,4L and other 4L, 2D
Instead, question is asking for the fraction that you get as : number of possible codes for S-2 / number of possible codes for S-1
(eg, say if possible number of S-1 is 100 then what fraction of it is S-2 which is 20. re-reading the question now should help
)S-1 = 10*10*20*20*20*20
(Question has no restriction on repeating the digit or letter)
S-2 = 10*10*10*10*20*20
Hence, Ans = S-2/S-1 = 1/4
Hope it helps.
09 Nov 2012, 04:12
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Oh, got it!
what fraction of outcome s-1 is outcome s-2......
Thanks Vips0000.
what fraction of outcome s-1 is outcome s-2......
Thanks Vips0000.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
