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30 Jun 2017, 06:57
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Suppose P, Q, R, and S are integers. If P is even and (P*Q + R*S) is an odd integer, then which of the following must be true?
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
30 Jun 2017, 07:16
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mkrishnabdrr
Suppose P, Q, R, and S are integers. If P is even and (P*Q + R*S) is an odd integer, then which of the following must be true?
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
PQ + RS = odd
even*Q + RS = odd
even + RS = odd (PQ will be even regardless of Q)
RS = odd - even = odd
The product of two integers to be odd both must be odd.
Answer: D.
30 Jun 2017, 07:18
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mkrishnabdrr
Suppose P, Q, R, and S are integers. If P is even and (P*Q + R*S) is an odd integer, then which of the following must be true?
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
i. Q is odd
ii. R is odd
iii. S is odd
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III only
(P*Q + R*S) = Odd integer,
P = Even Integer
So,
Even Integer + Odd Integer = Odd Integer
On LHS, for 2nd item (RS) to be ODD, both R & S has to be odd
Even if Q is EVEN, result wouln't change
Hence Answer D
