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Bunuel
Susan spent one-third of her money on books and half of the remaining money on clothing. She then spent three-fourths of what she had left on food. She had $5 left over. How much money did she start with?


A. $60
B. $80
C. $120
D. $160
E. $180

We can let the total amount of money Susan had = n.

So she spent n/3 on books, (1/2)(n - n/3) = (1/2)(2n/3) = n/3 on clothing and (3/4)(n - n/3 - n/3) = (3/4)(n/3) = n/4 on food. We can create the equation:

n/3 + n/3 + n/4 + 5 = n

Multiplying the equation by 12, we have:

4n + 4n + 3n + 60 = 12n

11n + 60 = 12n

60 = n

So she had $60 before she spent it on books, clothing and food.

Answer: A
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Abhishek009
Bunuel
Susan spent one-third of her money on books and half of the remaining money on clothing. She then spent three-fourths of what she had left on food. She had $5 left over. How much money did she start with?


A. $60
B. $80
C. $120
D. $160
E. $180

Let the amount of money she had be 12x

Amount spent on books = 4x
Amount spent on clothing = 4x
Amount spent on food = 3x
Amount left = x = $5

So, the total amount of money she had is $ 60, Answer must be (A)





Please how did your get your 60,
from your calculations there is really no way x=$5
will turn to 60
what am i missing

please assist
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Fractions and equations are current subject at the gmat test.
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Bunuel
Susan spent one-third of her money on books and half of the remaining money on clothing. She then spent three-fourths of what she had left on food. She had $5 left over. How much money did she start with?


A. $60
B. $80
C. $120
D. $160
E. $180

We need something that's divisible by 3. B and D are out.
Let's just try C. If we need something smaller, it's A; if we need something larger, it's E.

She starts with $120.
She spends $40 on books and has $80 remaining.
She spends $40 on clothing and has $40 remaining.
She spends $30 on food and has $10 remaining. We want her to have $5 remaining, so $10 is too much. We need something smaller.

Answer choice A.
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